﻿ Python: Check if a nested list is a subset of another nested list - w3resource

# Python: Check if a nested list is a subset of another nested list

## Python List: Exercise - 92 with Solution

Write a Python program to check if a nested list is a subset of another nested list.

Sample Solution:

Python Code:

``````def checkSubset(input_list1, input_list2):
return all(map(input_list1.__contains__, input_list2))

list1 = [[1, 3], [5, 7], [9, 11], [13, 15, 17]]
list2 = [[1, 3],[13,15,17]]
print("Original list:")
print(list1)
print(list2)
print("\nIf the one of the said list is a subset of another.:")
print(checkSubset(list1, list2))

list1 = [
[
[1,2],[2,3]
],
[
[3,4],[5,6]
]
]
list2 = [
[
[3,4], [5, 6]
]
]
print("Original list:")
print(list1)
print(list2)
print("\nIf the one of the said list is a subset of another.:")
print(checkSubset(list1, list2))
list1 = [
[
[1,2],[2,3]
],
[
[3,4],[5,7]
]
]
list2 = [
[
[3,4], [5, 6]
]
]
print("Original list:")
print(list1)
print(list2)
print("\nIf the one of the said list is a subset of another.:")
print(checkSubset(list1, list2))
```
```

Sample Output:

```Original list:
[[1, 3], [5, 7], [9, 11], [13, 15, 17]]
[[1, 3], [13, 15, 17]]

If the one of the said list is a subset of another.:
True
Original list:
[[[1, 2], [2, 3]], [[3, 4], [5, 6]]]
[[[3, 4], [5, 6]]]

If the one of the said list is a subset of another.:
True
Original list:
[[[1, 2], [2, 3]], [[3, 4], [5, 7]]]
[[[3, 4], [5, 6]]]

If the one of the said list is a subset of another.:
False
```

Pictorial Presentation: Flowchart: ## Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:

Python Code Editor:

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﻿

## Python: Tips of the Day

Given a predicate function, fn, and a prop string, this curried function will then take an object to inspect by calling the property and passing it to the predicate:

Example:

```def tips_check_prop(fn, prop):
return lambda obj: fn(obj[prop])
check_age = tips_check_prop(lambda x: x >= 25, 'age')
user = {'name': 'Owen', 'age': 25}

print(check_age(user))
```

Output:

```True
```

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