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Python Math: Returns sum of all divisors of a number

Python Math: Exercise-15 with Solution

Write a Python program to returns sum of all divisors of a number.

Sample Solution:-

Python Code:

def sum_div(number):
    divisors = [1]
    for i in range(2, number):
        if (number % i)==0:
            divisors.append(i)
    return sum(divisors)
print(sum_div(8))
print(sum_div(12))

Sample Output:

7
16

Pictorial Presentation:

Python Math: Returns sum of all divisors of a number

Flowchart:

Flowchart: Returns sum of all divisors of a number

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Python: Tips of the Day

Lambdas for Sorting:

>>> students = [{'name': 'John', 'score': 98}, {'name': 'Mike', 'score': 94}, {'name': 'Jennifer', 'score': 99}]
>>> sorted(students, key=lambda x: x['score'])
[{'name': 'Mike', 'score': 94}, {'name': 'John', 'score': 98}, {'name': 'Jennifer', 'score': 99}]