# Python Math: Returns sum of all divisors of a number

## Python Math: Exercise-15 with Solution

Write a Python program to return the sum of all divisors of a number.

**Sample Solution**:

**Python Code:**

```
def sum_div(number):
divisors = [1]
for i in range(2, number):
if (number % i)==0:
divisors.append(i)
return sum(divisors)
print(sum_div(8))
print(sum_div(12))
```

Sample Output:

7 16

**Pictorial Presentation:**

**Flowchart:**

**Python Code Editor:**

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