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Python Math: Get the local and default precision

Python Math: Exercise-42 with Solution

Write a Python program to get the local and default precision.

Sample Solution:-

Python Code:

import decimal
with decimal.localcontext() as context:
    context.prec = 2
    print('Local precision:', context.prec)
    print('22/7 =', (decimal.Decimal('22') / 7))

print()
print('Default precision:', decimal.getcontext().prec)
print('22 /7 =', (decimal.Decimal('22') / 7))

Sample Output:

Local precision: 2                                                                                            
22/7 = 3.1                                                                                                    
                                                                                                              
Default precision: 28                                                                                         
22 /7 = 3.142857142857142857142857143

Flowchart:

Flowchart: Get the local and default precision

Python Code Editor:

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Lambdas for Sorting:

>>> students = [{'name': 'John', 'score': 98}, {'name': 'Mike', 'score': 94}, {'name': 'Jennifer', 'score': 99}]
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