Python Math: Get the local and default precision

Python Math: Exercise-42 with Solution

Write a Python program to get the local and default precision.

Sample Solution:-

Python Code:

import decimal
with decimal.localcontext() as context:
    context.prec = 2
    print('Local precision:', context.prec)
    print('22/7 =', (decimal.Decimal('22') / 7))

print('Default precision:', decimal.getcontext().prec)
print('22 /7 =', (decimal.Decimal('22') / 7))

Sample Output:

Local precision: 2                                                                                            
22/7 = 3.1                                                                                                    
Default precision: 28                                                                                         
22 /7 = 3.142857142857142857142857143


Flowchart: Get the local and default precision

Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Write a Python program to round a specified number upwards towards infinity and down towards negative infinity of precision 4.
Next: Write a Python program to display the fraction instances of the string representation of a number.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.

Share this Tutorial / Exercise on : Facebook and Twitter

Python: Tips of the Day

Lambdas for Sorting:

>>> students = [{'name': 'John', 'score': 98}, {'name': 'Mike', 'score': 94}, {'name': 'Jennifer', 'score': 99}]
>>> sorted(students, key=lambda x: x['score'])
[{'name': 'Mike', 'score': 94}, {'name': 'John', 'score': 98}, {'name': 'Jennifer', 'score': 99}]