w3resource

NumPy: Compute the multiplication of two given matrixes

NumPy: Linear Algebra Exercise-1 with Solution

Write a NumPy program to compute the multiplication of two given matrixes.

Sample Matrix:

[[1, 0], [0, 1]]
[[1, 2], [3, 4]]

Matrix multiplication, and the detailed calculation:

NumPy Linear algebra: Compute the multiplication of two given matrixes

Sample Solution :

Python Code :

import numpy as np
p = [[1, 0], [0, 1]]
q = [[1, 2], [3, 4]]
print("original matrix:")
print(p)
print(q)
result1 = np.dot(p, q)
print("Result of the said matrix multiplication:")
print(result1)
print(result2)

Sample Output:

original matrix:
[[1, 0], [0, 1]]
[[1, 2], [3, 4]]
Result of the said matrix multiplication:
[[1 2]
 [3 4]]

Python Code Editor:


Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: NumPy Exercises Home.
Next: Write a NumPy program to compute the outer product of two given vectors.

What is the difficulty level of this exercise?

Test your Python skills with w3resource's quiz



Python: Tips of the Day

Getting the last element of a list:

some_list[-1] is the shortest and most Pythonic.

In fact, you can do much more with this syntax. The some_list[-n] syntax gets the nth-to-last element. So some_list[-1] gets the last element, some_list[-2] gets the second to last, etc, all the way down to some_list[-len(some_list)], which gives you the first element.

You can also set list elements in this way. For instance:

>>> some_list = [1, 2, 3]
>>> some_list[-1] = 5 # Set the last element
>>> some_list[-2] = 3 # Set the second to last element
>>> some_list
[1, 3, 5]

Note that getting a list item by index will raise an IndexError if the expected item doesn't exist. This means that some_list[-1] will raise an exception if some_list is empty, because an empty list can't have a last element.

Ref: https://bit.ly/3d8TfFP