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NumPy: Compute the cross product of two given vectors

NumPy: Linear Algebra Exercise-3 with Solution

Write a NumPy program to compute the cross product of two given vectors.

NumPy: Cross product of two vectors

NumPy Linear algebra: Compute the cross product of two given vectors

Sample Solution :

Python Code :

import numpy as np
p = [[1, 0], [0, 1]]
q = [[1, 2], [3, 4]]
print("original matrix:")
print(p)
print(q)
result1 = np.cross(p, q)
result2 = np.cross(q, p)
print("cross product of the said two vectors(p, q):")
print(result1)
print("cross product of the said two vectors(q, p):")
print(result2)

Sample Output:

original matrix:
[[1, 0], [0, 1]]
[[1, 2], [3, 4]]
cross product of the said two vectors(p, q):
[ 2 -3]
cross product of the said two vectors(q, p):
[-2  3]

Python Code Editor:


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Python: Tips of the Day

Getting the last element of a list:

some_list[-1] is the shortest and most Pythonic.

In fact, you can do much more with this syntax. The some_list[-n] syntax gets the nth-to-last element. So some_list[-1] gets the last element, some_list[-2] gets the second to last, etc, all the way down to some_list[-len(some_list)], which gives you the first element.

You can also set list elements in this way. For instance:

>>> some_list = [1, 2, 3]
>>> some_list[-1] = 5 # Set the last element
>>> some_list[-2] = 3 # Set the second to last element
>>> some_list
[1, 3, 5]

Note that getting a list item by index will raise an IndexError if the expected item doesn't exist. This means that some_list[-1] will raise an exception if some_list is empty, because an empty list can't have a last element.

Ref: https://bit.ly/3d8TfFP