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Pandas: Start index with different value rather than 0 in a given DataFrame

Pandas Indexing: Exercise-25 with Solution

Write a Pandas program to start index with different value rather than 0 in a given DataFrame.

Sample Solution:

Python Code :

import pandas as pd
df = pd.DataFrame({
    'school_code': ['s001','s002','s003','s001','s002','s004'],
    'class': ['V', 'V', 'VI', 'VI', 'V', 'VI'],
    'name': ['Alberto Franco','Gino Mcneill','Ryan Parkes', 'Eesha Hinton', 'Gino Mcneill', 'David Parkes'],
    'date_of_birth': ['15/05/2002','17/05/2002','16/02/1999','25/09/1998','11/05/2002','15/09/1997'],
    'weight': [35, 37, 33, 30, 31, 32]})
     
print("Original DataFrame:")
print(df)
print("\nDefault Index Range:")
print(df.index)
df.index += 10 
print("\nNew Index Range:")
print(df.index)
print("\nDataFrame with new index:")
print(df)

Sample Output:

Original DataFrame:
  school_code class            name date_of_birth  weight
0        s001     V  Alberto Franco    15/05/2002      35
1        s002     V    Gino Mcneill    17/05/2002      37
2        s003    VI     Ryan Parkes    16/02/1999      33
3        s001    VI    Eesha Hinton    25/09/1998      30
4        s002     V    Gino Mcneill    11/05/2002      31
5        s004    VI    David Parkes    15/09/1997      32

Default Index Range:
RangeIndex(start=0, stop=6, step=1)

New Index Range:
RangeIndex(start=10, stop=16, step=1)

DataFrame with new index:
   school_code class            name date_of_birth  weight
10        s001     V  Alberto Franco    15/05/2002      35
11        s002     V    Gino Mcneill    17/05/2002      37
12        s003    VI     Ryan Parkes    16/02/1999      33
13        s001    VI    Eesha Hinton    25/09/1998      30
14        s002     V    Gino Mcneill    11/05/2002      31
15        s004    VI    David Parkes    15/09/1997      32

Python Code Editor:


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Previous: Write a Pandas program to find integer index of rows with missing data in a given dataframe.
Next: Write a Pandas program to select rows by filtering on one or more column(s) in a multi-index dataframe.

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Python: Tips of the Day

How to sort a Python dict by value

Example:

x1 = {'a': 5, 'b': 7, 'c': 9, 'd': 1}

sorted(x1.items(), key=lambda x: x[1])
[('d', 1), ('c', 9), ('b', 7), ('a', 5)]

# Or:

import operator
print(sorted(x1.items(), key=operator.itemgetter(1)))

Output:

[('d', 1), ('a', 5), ('b', 7), ('c', 9)]