Pandas: Convert a specified character column in upper/lower cases in a given DataFrame
Pandas: String and Regular Expression Exercise-19 with Solution
Write a Pandas program to convert a specified character column in upper/lower cases in a given DataFrame.
Sample Solution:
Python Code :
import pandas as pd
df = pd.DataFrame({
'company_code': ['Abcd','EFGF', 'zefsalf', 'sdfslew', 'zekfsdf'],
'date_of_sale': ['12/05/2002','16/02/1999','25/09/1998','12/02/2022','15/09/1997'],
'sale_amount': [12348.5, 233331.2, 22.5, 2566552.0, 23.0]
})
df1 = pd.DataFrame({
'company_code': ['Abcd','EFGF', 'zefsalf', 'sdfslew', 'zekfsdf'],
'date_of_sale': ['12/05/2002','16/02/1999','25/09/1998','12/02/2022','15/09/1997'],
'sale_amount': [12348.5, 233331.2, 22.5, 2566552.0, 23.0]
})
print("Original DataFrame:")
print(df)
print("\nUpper cases in comapny_code:")
df['upper_company_code'] = list(map(lambda x: x.upper(), df['company_code']))
print(df)
print("\nLower cases in comapny_code:")
df1['lower_company_code'] = list(map(lambda x: x.lower(), df1['company_code']))
print(df1)
Sample Output:
Original DataFrame: company_code date_of_sale sale_amount 0 Abcd 12/05/2002 12348.5 1 EFGF 16/02/1999 233331.2 2 zefsalf 25/09/1998 22.5 3 sdfslew 12/02/2022 2566552.0 4 zekfsdf 15/09/1997 23.0 Upper cases in comapny_code: company_code date_of_sale sale_amount upper_company_code 0 Abcd 12/05/2002 12348.5 ABCD 1 EFGF 16/02/1999 233331.2 EFGF 2 zefsalf 25/09/1998 22.5 ZEFSALF 3 sdfslew 12/02/2022 2566552.0 SDFSLEW 4 zekfsdf 15/09/1997 23.0 ZEKFSDF Lower cases in comapny_code: company_code date_of_sale sale_amount lower_company_code 0 Abcd 12/05/2002 12348.5 abcd 1 EFGF 16/02/1999 233331.2 efgf 2 zefsalf 25/09/1998 22.5 zefsalf 3 sdfslew 12/02/2022 2566552.0 sdfslew 4 zekfsdf 15/09/1997 23.0 zekfsdf
Python Code Editor:
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