Python: Filter for the numbers in a list whose sum of digits is >0, where the first digit can be negative

Last update on April 17 2025 13:02:56 (UTC/GMT +8 hours)

Filter by Sum of Digits

Write a Python program to filter for numbers in a given list whose sum of digits is > 0, where the first digit can be negative.

Input:
[11, -6, -103, -200]
Output:
[11, -103]

Input:
[1, 7, -4, 4, -9, 2]
Output:
[1, 7, 4, 2]

Input:
[10, -11, -71, -13, 14, -32]
Output:
[10, -13, 14]

Sample Solution:

Python Code:

# Define a function named 'test' that takes a list of numbers 'nums' as input
def test(nums):
    # Use a list comprehension to filter numbers based on the sum of their digits
    return [n for n in nums if int(str(n)[:2]) + sum(map(int, str(n)[2:])) > 0]

# Assign a specific list of numbers to the variable 'nums'
nums =  [11, -6, -103, -200]
# Print a message indicating the original list of numbers
print("Original list:")
# Print the original list of numbers
print(nums)
# Print a message indicating the numbers whose sum of digits is >0, allowing negative first digits
print("Find the numbers in the said list whose sum of digits is >0, where the first digit can be negative:")
# Print the result of the test function applied to 'nums'
print(test(nums))

# Assign another specific list of numbers to the variable 'nums'
nums =  [1, 7, -4, 4, -9, 2]
# Print a message indicating the original list of numbers
print("\nOriginal list:")
# Print the original list of numbers
print(nums)
# Print a message indicating the numbers whose sum of digits is >0, allowing negative first digits
print("Find the numbers in the said list whose sum of digits is >0, where the first digit can be negative:")
# Print the result of the test function applied to 'nums'
print(test(nums))

# Assign another specific list of numbers to the variable 'nums'
nums =  [10, -11, -71, -13, 14, -32]
# Print a message indicating the original list of numbers
print("\nOriginal list:")
# Print the original list of numbers
print(nums)
# Print a message indicating the numbers whose sum of digits is >0, allowing negative first digits
print("Find the numbers in the said list whose sum of digits is >0, where the first digit can be negative:")
# Print the result of the test function applied to 'nums'
print(test(nums))

Sample Output:

Original list:
[11, -6, -103, -200]
Find the numbers in the said list whose sum of digits is >0, where the first digit can be negative:
[11, -103]

Original list:
[1, 7, -4, 4, -9, 2]
Find the numbers in the said list whose sum of digits is >0, where the first digit can be negative:
[1, 7, 4, 2]

Original list:
[10, -11, -71, -13, 14, -32]
Find the numbers in the said list whose sum of digits is >0, where the first digit can be negative:
[10, -13, 14]

Flowchart:

For more Practice: Solve these Related Problems:

Write a Python program to filter a list of integers and return those whose sum of digits is greater than 0, handling negative first digits.
Write a Python program to compute the digit sum for each number and select only those with a positive digit sum.
Write a Python program to iterate over a list and include numbers with non-zero digit sums in the output list.
Write a Python program to use lambda functions to filter numbers by verifying that the sum of their digits exceeds zero.

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Next: Find the indices of two entries that show that the list is not in increasing order.

Python Code Editor :

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