Python: Separate parentheses groups
Python Programming Puzzles: Exercise-94 with Solution
Given a string consisting of whitespace and groups of matched parentheses, write a Python program to split it into groups of perfectly matched parentheses without any whitespace.
Input: ( ()) ((()()())) (()) () Output: ['(())', '((()()()))', '(())', '()'] Input: () (( ( )() ( )) ) ( ()) Output: ['()', '((()()()))', '(())']
Sample Solution:
Python Code:
#License: https://bit.ly/3oLErEI
def test(combined):
ls = []
s2 = ""
for s in combined.replace(' ', ''):
s2 += s
if s2.count("(") == s2.count(")"):
ls.append(s2)
s2 = ""
return ls
combined = '( ()) ((()()())) (()) ()'
print("Parentheses string:")
print(combined)
print("Separate parentheses groups of the said string:")
print(test(combined))
combined = '() (( ( )() ( )) ) ( ())'
print("\nParentheses string:")
print(combined)
print("Separate parentheses groups of the said string:")
print(test(combined))
Sample Output:
Parentheses string: ( ()) ((()()())) (()) () Separate parentheses groups of the said string: ['(())', '((()()()))', '(())', '()'] Parentheses string: () (( ( )() ( )) ) ( ()) Separate parentheses groups of the said string: ['()', '((()()()))', '(())']
Flowchart:

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Python: Tips of the Day
Clamps num within the inclusive range specified by the boundary values x and y:
Example:
def tips_clamp_num(num,x,y): return max(min(num, max(x, y)), min(x, y)) print(tips_clamp_num(2, 4, 6)) print(tips_clamp_num(1, -1, -6))
Output:
4 -1
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