Python: Search some literals strings in a string
Python Regular Expression: Exercise-19 with Solution
Write a Python program to search some literals strings in a string.
import re patterns = [ 'fox', 'dog', 'horse' ] text = 'The quick brown fox jumps over the lazy dog.' for pattern in patterns: print('Searching for "%s" in "%s" ->' % (pattern, text),) if re.search(pattern, text): print('Matched!') else: print('Not Matched!')
Searching for "fox" in "The quick brown fox jumps over the lazy dog." -> Matched! Searching for "dog" in "The quick brown fox jumps over the lazy dog." -> Matched! Searching for "horse" in "The quick brown fox jumps over the lazy dog." -> Not Matched!
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Previous: Write Python program to search the numbers (0-9) of length between 1 to 3 in a given string.
Next: Write a Python program to search a literals string in a string and also find the location within the original string where the pattern occurs.
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Python: Tips of the Day
Getting the last element of a list:
some_list[-1] is the shortest and most Pythonic.
In fact, you can do much more with this syntax. The some_list[-n] syntax gets the nth-to-last element. So some_list[-1] gets the last element, some_list[-2] gets the second to last, etc, all the way down to some_list[-len(some_list)], which gives you the first element.
You can also set list elements in this way. For instance:
>>> some_list = [1, 2, 3] >>> some_list[-1] = 5 # Set the last element >>> some_list[-2] = 3 # Set the second to last element >>> some_list [1, 3, 5]
Note that getting a list item by index will raise an IndexError if the expected item doesn't exist. This means that some_list[-1] will raise an exception if some_list is empty, because an empty list can't have a last element.
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