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Python: Search a literals string in a string and also find the location where the pattern occurs

Python Regular Expression: Exercise-20 with Solution

Write a Python program to search a literals string in a string and also find the location within the original string where the pattern occurs.

Sample Solution:-

Python Code:

import re
pattern = 'fox'
text = 'The quick brown fox jumps over the lazy dog.'
match = re.search(pattern, text)
s = match.start()
e = match.end()
print('Found "%s" in "%s" from %d to %d ' % \
    (match.re.pattern, match.string, s, e))
	

Sample Output:

Found "fox" in "The quick brown fox jumps over the lazy dog." from 16 to 19 

Pictorial Presentation:

Python: Regular Expression - Search a literals string in a string and also find the location where the pattern occurs.

Flowchart:

Flowchart: Regular Expression - Search a literals string in a string and also find the location where the pattern occurs.

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Python: Tips of the Day

Getting the last element of a list:

some_list[-1] is the shortest and most Pythonic.

In fact, you can do much more with this syntax. The some_list[-n] syntax gets the nth-to-last element. So some_list[-1] gets the last element, some_list[-2] gets the second to last, etc, all the way down to some_list[-len(some_list)], which gives you the first element.

You can also set list elements in this way. For instance:

>>> some_list = [1, 2, 3]
>>> some_list[-1] = 5 # Set the last element
>>> some_list[-2] = 3 # Set the second to last element
>>> some_list
[1, 3, 5]

Note that getting a list item by index will raise an IndexError if the expected item doesn't exist. This means that some_list[-1] will raise an exception if some_list is empty, because an empty list can't have a last element.

Ref: https://bit.ly/3d8TfFP