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Python: Check a decimal with a precision of 2

Python Regular Expression: Exercise-48 with Solution

Write a Python program to check a decimal with a precision of 2.

Sample Solution:-

Python Code:

def is_decimal(num):
    import re
    dnumre = re.compile(r"""^[0-9]+(\.[0-9]{1,2})?$""")
    result = dnumre.search(num)
    return bool(result)

print(is_decimal('123.11'))
print(is_decimal('123.1'))
print(is_decimal('123'))
print(is_decimal('0.21'))

print(is_decimal('123.1214'))
print(is_decimal('3.124587'))
print(is_decimal('e666.86'))

Sample Output:

True                                                                                                          
True                                                                                                          
True                                                                                                          
True                                                                                                          
False                                                                                                         
False                                                                                                         
False

Pictorial Presentation:

Python: Regular Expression - Check a decimal with a precision of 2.
Python: Regular Expression - Check a decimal with a precision of 2.

Flowchart:

Flowchart: Regular Expression - Check a decimal with a precision of 2.

Python Code Editor:

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Next: Write a Python program to remove words from a string of length between 1 and a given number.

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Python: Tips of the Day

For-else construct useful when searched for something and find it:

# For example assume that I need to search through a list and process each item until a flag item is found and 
# then stop processing. If the flag item is missing then an exception needs to be raised.

for i in mylist:
    if i == theflag:
        break
    process(i)
else:
    raise ValueError("List argument missing terminal flag.")