﻿ Python: Check a decimal with a precision of 2 - w3resource

# Python: Check a decimal with a precision of 2

## Python Regular Expression: Exercise-48 with Solution

Write a Python program to check a decimal with a precision of 2.

Sample Solution:-

Python Code:

``````def is_decimal(num):
import re
dnumre = re.compile(r"""^[0-9]+(\.[0-9]{1,2})?\$""")
result = dnumre.search(num)
return bool(result)

print(is_decimal('123.11'))
print(is_decimal('123.1'))
print(is_decimal('123'))
print(is_decimal('0.21'))

print(is_decimal('123.1214'))
print(is_decimal('3.124587'))
print(is_decimal('e666.86'))
```
```

Sample Output:

```True
True
True
True
False
False
False
```

Pictorial Presentation:

Flowchart:

Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

What is the difficulty level of this exercise?

Test your Python skills with w3resource's quiz

﻿

## Python: Tips of the Day

Getting the last element of a list:

some_list[-1] is the shortest and most Pythonic.

In fact, you can do much more with this syntax. The some_list[-n] syntax gets the nth-to-last element. So some_list[-1] gets the last element, some_list[-2] gets the second to last, etc, all the way down to some_list[-len(some_list)], which gives you the first element.

You can also set list elements in this way. For instance:

```>>> some_list = [1, 2, 3]
>>> some_list[-1] = 5 # Set the last element
>>> some_list[-2] = 3 # Set the second to last element
>>> some_list
[1, 3, 5]
```

Note that getting a list item by index will raise an IndexError if the expected item doesn't exist. This means that some_list[-1] will raise an exception if some_list is empty, because an empty list can't have a last element.

Ref: https://bit.ly/3d8TfFP