w3resource

Python: Check a decimal with a precision of 2

Python Regular Expression: Exercise-48 with Solution

Write a Python program to check a decimal with a precision of 2.

Sample Solution:-

Python Code:

def is_decimal(num):
    import re
    dnumre = re.compile(r"""^[0-9]+(\.[0-9]{1,2})?$""")
    result = dnumre.search(num)
    return bool(result)

print(is_decimal('123.11'))
print(is_decimal('123.1'))
print(is_decimal('123'))
print(is_decimal('0.21'))

print(is_decimal('123.1214'))
print(is_decimal('3.124587'))
print(is_decimal('e666.86'))

Sample Output:

True                                                                                                          
True                                                                                                          
True                                                                                                          
True                                                                                                          
False                                                                                                         
False                                                                                                         
False

Pictorial Presentation:

Python: Regular Expression - Check a decimal with a precision of 2.
Python: Regular Expression - Check a decimal with a precision of 2.

Flowchart:

Flowchart: Regular Expression - Check a decimal with a precision of 2.

Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Write a Python program to split a string with multiple delimiters.
Next: Write a Python program to remove words from a string of length between 1 and a given number.

What is the difficulty level of this exercise?

Test your Python skills with w3resource's quiz



Python: Tips of the Day

Getting the last element of a list:

some_list[-1] is the shortest and most Pythonic.

In fact, you can do much more with this syntax. The some_list[-n] syntax gets the nth-to-last element. So some_list[-1] gets the last element, some_list[-2] gets the second to last, etc, all the way down to some_list[-len(some_list)], which gives you the first element.

You can also set list elements in this way. For instance:

>>> some_list = [1, 2, 3]
>>> some_list[-1] = 5 # Set the last element
>>> some_list[-2] = 3 # Set the second to last element
>>> some_list
[1, 3, 5]

Note that getting a list item by index will raise an IndexError if the expected item doesn't exist. This means that some_list[-1] will raise an exception if some_list is empty, because an empty list can't have a last element.

Ref: https://bit.ly/3d8TfFP