Python: Check if two given sets have no elements in common

Last update on July 05 2025 07:29:20 (UTC/GMT +8 hours)

17. Check if Two Sets Have No Elements in Common

Write a Python program to check if two given sets have no elements in common.

Visual Presentation:

Sample Solution-1:

Python Code:

# Create sets 'x', 'y', and 'z' with different elements.
x = {1, 2, 3, 4}
y = {4, 5, 6, 7}
z = {8}

# Print a message to indicate the original set elements.
print("Original set elements:")
print(x)
print(y)
print(z)

# Print a message to confirm that two given sets have no common elements.
print("\nConfirm two given sets have no element(s) in common:")

# Print a message to indicate comparing sets 'x' and 'y'.
print("\nCompare x and y:")

# Use the 'isdisjoint()' method to check if 'x' and 'y' have no common elements and print the result.
print(x.isdisjoint(y))

# Print a message to indicate comparing sets 'x' and 'z'.
print("\nCompare x and z:")

# Use the 'isdisjoint()' method to check if 'x' and 'z' have no common elements and print the result.
print(z.isdisjoint(x))

# Print a message to indicate comparing sets 'y' and 'z'.
print("\nCompare y and z:")

# Use the 'isdisjoint()' method to check if 'y' and 'z' have no common elements and print the result.
print(y.isdisjoint(z)) 

Sample Output:

Original set elements:
{1, 2, 3, 4}
{4, 5, 6, 7}
{8}

Confirm two given sets have no element(s) in common:

Compare x and y:
False

Compare x and z:
True

Compare y and z:
True

Sample Solution-2:

Python Code:

# Define a function 'compare_sets' to check if two sets have no common elements.
def compare_sets(s1, s2):
    for i in s1:
        if i in s2:
            return False
    return True

# Create sets 'x', 'y', and 'z' with different elements.
x = {1, 2, 3, 4}
y = {4, 5, 6, 7}
z = {8}

# Print a message to indicate the original set elements.
print("Original set elements:")
print(x)
print(y)
print(z)

# Print a message to confirm that two given sets have no common elements.
print("\nConfirm two given sets have no element(s) in common:")

# Print a message to indicate comparing sets 'x' and 'y'.
print("\nCompare x and y:")

# Call the 'compare_sets' function to check if 'x' and 'y' have no common elements and print the result.
print(compare_sets(x, y))

# Print a message to indicate comparing sets 'x' and 'z'.
print("\nCompare x and z:")

# Call the 'compare_sets' function to check if 'x' and 'z' have no common elements and print the result.
print(compare_sets(x, z))

# Print a message to indicate comparing sets 'y' and 'z'.
print("\nCompare y and z:")

# Call the 'compare_sets' function to check if 'y' and 'z' have no common elements and print the result.
print(compare_sets(y, z)) 

Sample Output:

Original set elements:
{1, 2, 3, 4}
{4, 5, 6, 7}
{8}

Confirm two given sets have no element(s) in common:

Compare x and y:
False

Compare x and z:
True

Compare y and z:
True

Flowchart:

For more Practice: Solve these Related Problems:

• Write a Python program to determine if two sets are disjoint using the isdisjoint() method.
• Write a Python program to check for common elements in two sets using set intersection and return True if none are found.
• Write a Python program to implement a function that takes two sets and returns True if they share no common elements.
• Write a Python program to compare two sets using the & operator and verify that the result is an empty set.

Go to:

• Python Data Types Sets Exercises Home ↩
• Python Exercises Home ↩

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