Python: Add two strings as they are numbers (Positive integer values)
Python String: Exercise-101 with Solution
Write a Python program to add two strings as they are numbers (Positive integer values). Return a message if the numbers are string.
Sample Solution-1:
Python Code:
def test(n1, n2):
n1, n2 = '0' + n1, '0' + n2
if (n1.isnumeric() and n2.isnumeric()):
return str(int(n1) + int(n2))
else:
return 'Error in input!'
print(test("10", "32"))
print(test("10", "22.6"))
print(test("100", "-200"))
Sample Output:
42 Error in input! Error in input!
Flowchart:

Visualize Python code execution:
The following tool visualize what the computer is doing step-by-step as it executes the said program:
Sample Solution-2:
Python Code:
def test(n1, n2):
if n1 == '':
n1= '0'
if n2 == '':
n2 = '0'
if n1.isdigit() and n2.isdigit():
return str(int(n1)+int(n2))
return 'Error in input!'
print(test("23", "43"))
print(test("12", "11.6"))
print(test("200", "-100"))
Sample Output:
66 Error in input! Error in input!
Flowchart:

Visualize Python code execution:
The following tool visualize what the computer is doing step-by-step as it executes the said program:
Python Code Editor:
Have another way to solve this solution? Contribute your code (and comments) through Disqus.
Previous: Write a Python program to check whether any word in a given sting contains duplicate characrters or not. Return True or False.
Next: Python List Exercise Home.
What is the difficulty level of this exercise?
Test your Programming skills with w3resource's quiz.
Python: Tips of the Day
Check if a given key already exists in a dictionary:
In is the intended way to test for the existence of a key in a dict.
d = {"key1": 10, "key2": 23} if "key1" in d: print("this will execute") if "nonexistent key" in d: print("this will not")
If you wanted a default, you can always use dict.get():
d = dict() for i in range(100): key = i % 10 d[key] = d.get(key, 0) + 1
and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:
from collections import defaultdict d = defaultdict(int) for i in range(100): d[i % 10] += 1
but in general, the in keyword is the best way to do it.
Ref: https://bit.ly/2XPMRyz
- New Content published on w3resource:
- HTML-CSS Practical: Exercises, Practice, Solution
- Java Regular Expression: Exercises, Practice, Solution
- Scala Programming Exercises, Practice, Solution
- Python Itertools exercises
- Python Numpy exercises
- Python GeoPy Package exercises
- Python Pandas exercises
- Python nltk exercises
- Python BeautifulSoup exercises
- Form Template
- Composer - PHP Package Manager
- PHPUnit - PHP Testing
- Laravel - PHP Framework
- Angular - JavaScript Framework
- Vue - JavaScript Framework
- Jest - JavaScript Testing Framework