Python: Remove the characters which have odd index values of a given string
Python String: Exercise-11 with Solution
Write a Python program to remove the characters which have odd index values of a given string.

Sample Solution:-
Python Code:
def odd_values_string(str):
result = ""
for i in range(len(str)):
if i % 2 == 0:
result = result + str[i]
return result
print(odd_values_string('abcdef'))
print(odd_values_string('python'))
Sample Output:
ace pto
Flowchart:

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Previous: Write a Python program to change a given string to a new string where the first and last chars have been exchanged.
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Python: Tips of the Day
Check if a given key already exists in a dictionary:
In is the intended way to test for the existence of a key in a dict.
d = {"key1": 10, "key2": 23} if "key1" in d: print("this will execute") if "nonexistent key" in d: print("this will not")
If you wanted a default, you can always use dict.get():
d = dict() for i in range(100): key = i % 10 d[key] = d.get(key, 0) + 1
and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:
from collections import defaultdict d = defaultdict(int) for i in range(100): d[i % 10] += 1
but in general, the in keyword is the best way to do it.
Ref: https://bit.ly/2XPMRyz
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