Python: Count the occurrences of each word in a given sentence
Python String: Exercise-12 with Solution
Write a Python program to count the occurrences of each word in a given sentence.

Sample Solution:-
Python Code:
def word_count(str):
counts = dict()
words = str.split()
for word in words:
if word in counts:
counts[word] += 1
else:
counts[word] = 1
return counts
print( word_count('the quick brown fox jumps over the lazy dog.'))
Sample Output:
{'the': 2, 'jumps': 1, 'brown': 1, 'lazy': 1, 'fox': 1, 'over': 1, 'quick': 1, 'dog.': 1}
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Python: Tips of the Day
Check if a given key already exists in a dictionary:
In is the intended way to test for the existence of a key in a dict.
d = {"key1": 10, "key2": 23} if "key1" in d: print("this will execute") if "nonexistent key" in d: print("this will not")
If you wanted a default, you can always use dict.get():
d = dict() for i in range(100): key = i % 10 d[key] = d.get(key, 0) + 1
and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:
from collections import defaultdict d = defaultdict(int) for i in range(100): d[i % 10] += 1
but in general, the in keyword is the best way to do it.
Ref: https://bit.ly/2XPMRyz
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