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Python: Make two given strings anagrams removing any characters from any of the strings

Python String: Exercise-66 with Solution

Write a Python program to make two given strings (lower case, may or may not be of the same length) anagrams removing any characters from any of the strings.

Sample Solution:-

Python Code:

def make_map(s):
    temp_map = {}
    for char in s:
        if char not in temp_map:
            temp_map[char] = 1
        else:
            temp_map[char] +=1 
    return temp_map        
def make_anagram(str1, str2):
    str1_map1 = make_map(str1)
    str2_map2 = make_map(str2)
 
    ctr = 0
    for key in str2_map2.keys():
        if key not in str1_map1:
            ctr += str2_map2[key]
        else:
            ctr += max(0, str2_map2[key]-str1_map1[key])
 
    for key in str1_map1.keys():
        if key not in str2_map2:
            ctr += str1_map1[key]
        else:
            ctr += max(0, str1_map1[key]-str2_map2[key]) 
    return ctr 
str1 = input("Input string1: ")
str2 = input("Input string2: ")
print(make_anagram(str1, str2))

Sample Output:

Input string1:  The quick brown fox
Input string2:  jumps over the lazy dog
24

Pictorial Presentation:

Python String: Make two given strings anagrams removing any characters from any of the strings.

Flowchart:

Flowchart: Make two given strings anagrams removing any characters from any of the strings

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Python Code Editor:

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Previous: Write a Python program to find all the common characters in lexicographical order from two given lower case strings. If there are no common letters print “No common characters”.
Next: Write a Python program to remove all consecutive duplicates of a given string.

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Python: Tips of the Day

Check if a given key already exists in a dictionary:

In is the intended way to test for the existence of a key in a dict.

d = {"key1": 10, "key2": 23}

if "key1" in d:
    print("this will execute")

if "nonexistent key" in d:
    print("this will not")

If you wanted a default, you can always use dict.get():

d = dict()

for i in range(100):
    key = i % 10
    d[key] = d.get(key, 0) + 1

and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:

from collections import defaultdict

d = defaultdict(int)

for i in range(100):
    d[i % 10] += 1

but in general, the in keyword is the best way to do it.

Ref: https://bit.ly/2XPMRyz