﻿ Python: Make two given strings anagrams removing any characters from any of the strings - w3resource

# Python: Make two given strings anagrams removing any characters from any of the strings

## Python String: Exercise-66 with Solution

Write a Python program to make two given strings (lower case, may or may not be of the same length) anagrams removing any characters from any of the strings.

Sample Solution:-

Python Code:

``````def make_map(s):
temp_map = {}
for char in s:
if char not in temp_map:
temp_map[char] = 1
else:
temp_map[char] +=1
return temp_map
def make_anagram(str1, str2):
str1_map1 = make_map(str1)
str2_map2 = make_map(str2)

ctr = 0
for key in str2_map2.keys():
if key not in str1_map1:
ctr += str2_map2[key]
else:
ctr += max(0, str2_map2[key]-str1_map1[key])

for key in str1_map1.keys():
if key not in str2_map2:
ctr += str1_map1[key]
else:
ctr += max(0, str1_map1[key]-str2_map2[key])
return ctr
str1 = input("Input string1: ")
str2 = input("Input string2: ")
print(make_anagram(str1, str2))
```
```

Sample Output:

```Input string1:  The quick brown fox
Input string2:  jumps over the lazy dog
24
```

Pictorial Presentation:

Flowchart:

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## Python: Tips of the Day

Check if a given key already exists in a dictionary:

In is the intended way to test for the existence of a key in a dict.

```d = {"key1": 10, "key2": 23}

if "key1" in d:
print("this will execute")

if "nonexistent key" in d:
print("this will not")
```

If you wanted a default, you can always use dict.get():

```d = dict()

for i in range(100):
key = i % 10
d[key] = d.get(key, 0) + 1
```

and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:

```from collections import defaultdict

d = defaultdict(int)

for i in range(100):
d[i % 10] += 1
```

but in general, the in keyword is the best way to do it.

Ref: https://bit.ly/2XPMRyz