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Python: Remove all consecutive duplicates of a given string

Python String: Exercise-67 with Solution

Write a Python program to remove all consecutive duplicates of a given string.

Sample Solution - 1:

Python Code:

from itertools import groupby 
def remove_all_consecutive(str1): 
	result_str = [] 
	for (key,group) in groupby(str1): 
		result_str.append(key) 

	return ''.join(result_str)
	
str1 = 'xxxxxyyyyy'
print("Original string:" + str1)
print("After removing consecutive duplicates: " + str1)
print(remove_all_consecutive(str1))

Sample Output:

Original string:xxxxxyyyyy
After removing consecutive duplicates: xxxxxyyyyy
xy

Pictorial Presentation:

Python String: Remove all consecutive duplicates of a given string.

Flowchart:

Flowchart: Remove all consecutive duplicates of a given string

Visualize Python code execution:

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Sample Solution - 2:

Python Code:

import itertools
def remove_consecutive_duplicates(s1):
     return (''.join(i for i, _ in itertools.groupby(s1)))

s1= "aabcdaee"
print("Original String: ",s1)
print("\nRemoving all consecutive duplicates:")
print(remove_consecutive_duplicates(s1))

Sample Output:

Original String:  aabcdaee

Removing all consecutive duplicates:
abcdae

Pictorial Presentation:

Python String: Remove all consecutive duplicates of a given string.

Flowchart:

Flowchart: Remove all consecutive duplicates of a given string

Python Code Editor:

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Previous: Write a Python program to make two given strings (lower case, may or may not be of the same length) anagrams removing any characters from any of the strings.
Next: Write a Python program to create two strings from a given string. Create the first string using those character which occurs only once and create the second string which consists of multi-time occurring characters in the said string.

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Python: Tips of the Day

Check if a given key already exists in a dictionary:

In is the intended way to test for the existence of a key in a dict.

d = {"key1": 10, "key2": 23}

if "key1" in d:
    print("this will execute")

if "nonexistent key" in d:
    print("this will not")

If you wanted a default, you can always use dict.get():

d = dict()

for i in range(100):
    key = i % 10
    d[key] = d.get(key, 0) + 1

and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:

from collections import defaultdict

d = defaultdict(int)

for i in range(100):
    d[i % 10] += 1

but in general, the in keyword is the best way to do it.

Ref: https://bit.ly/2XPMRyz