﻿ Python: Check whether a given string has a capital letter, a lower case letter, a number and specified length - w3resource

# Python: Check whether a given string has a capital letter, a lower case letter, a number and specified length

## Python String: Exercise-88 with Solution

Write a Python program to check whether a given string contains a capital letter, a lower case letter, a number and a minimum length.

Sample Solution:-

Python Code:

``````def check_string(s):
messg = []
if not any(x.isupper() for x in s):
messg.append('String must have 1 upper case character.')
if not any(x.islower() for x in s):
messg.append('String must have 1 lower case character.')
if not any(x.isdigit() for x in s):
messg.append('String must have 1 number.')
if len(s) < 8:
messg.append('String length should be atleast 8.')
if not messg:
messg.append('Valid string.')
return messg

s = input("Input the string: ")
print(check_string(s))
```
```

Sample Output:

```Input the string:  W3resource
['Valid string.']
```

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## Python: Tips of the Day

Check if a given key already exists in a dictionary:

In is the intended way to test for the existence of a key in a dict.

```d = {"key1": 10, "key2": 23}

if "key1" in d:
print("this will execute")

if "nonexistent key" in d:
print("this will not")
```

If you wanted a default, you can always use dict.get():

```d = dict()

for i in range(100):
key = i % 10
d[key] = d.get(key, 0) + 1
```

and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:

```from collections import defaultdict

d = defaultdict(int)

for i in range(100):
d[i % 10] += 1
```

but in general, the in keyword is the best way to do it.

Ref: https://bit.ly/2XPMRyz