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Python: Remove unwanted characters from a given string

Python String: Exercise-89 with Solution

Write a Python program to remove unwanted characters from a given string.

Sample Solution:-

Python Code:

def remove_chars(str1, unwanted_chars):
    for i in unwanted_chars:
        str1 = str1.replace(i, '')
    return str1



str1 = "Pyth*^on Exercis^es"
str2 = "A%^!B#*CD"

unwanted_chars = ["#", "*", "!", "^", "%"]
print ("Original String : " + str1)
print("After removing unwanted characters:")
print(remove_chars(str1, unwanted_chars))
print ("\nOriginal String : " + str2)
print("After removing unwanted characters:")
print(remove_chars(str2, unwanted_chars))

Sample Output:

Original String : Pyth*^on Exercis^es
After removing unwanted characters:
Python Exercises

Original String : A%^!B#*CD
After removing unwanted characters:
ABCD

Flowchart:

Flowchart: Check whether a given string has a capital letter, a lower case letter, a number and specified length.

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Python Code Editor:

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Previous: Write a Python program to check whether a given string contains a capital letter, a lower case letter, a number and a minimum length.
Next: Write a Python program to remove duplicate words from a given string.

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Python: Tips of the Day

Check if a given key already exists in a dictionary:

In is the intended way to test for the existence of a key in a dict.

d = {"key1": 10, "key2": 23}

if "key1" in d:
    print("this will execute")

if "nonexistent key" in d:
    print("this will not")

If you wanted a default, you can always use dict.get():

d = dict()

for i in range(100):
    key = i % 10
    d[key] = d.get(key, 0) + 1

and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:

from collections import defaultdict

d = defaultdict(int)

for i in range(100):
    d[i % 10] += 1

but in general, the in keyword is the best way to do it.

Ref: https://bit.ly/2XPMRyz