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Python: Convert a given string to camelcase

Python String: Exercise-96 with Solution

From Wikipedia,
Camel case (sometimes stylized as camelCase or CamelCase; also known as camel caps or more formally as medial capitals) is the practice of writing phrases without spaces or punctuation, indicating the separation of words with a single capitalized letter, and the first word starting with either case.

Write a Python program to convert a given string to camelcase.

  • Use re.sub() to replace any - or _ with a space, using the regexp r"(_|-)+".
  • Use str.title() to capitalize the first letter of each word and convert the rest to lowercase.
  • Finally, use str.replace() to remove spaces between words.

Sample Solution:

Python Code:

from re import sub

def camel_case(s):
  s = sub(r"(_|-)+", " ", s).title().replace(" ", "")
  return ''.join([s[0].lower(), s[1:]])
print(camel_case('JavaScript'))
print(camel_case('Foo-Bar'))
print(camel_case('foo_bar'))
print(camel_case('--foo.bar'))
print(camel_case('Foo-BAR'))
print(camel_case('fooBAR'))
print(camel_case('foo bar'))

Sample Output:

javascript
fooBar
fooBar
foo.Bar
fooBar
foobar
fooBar

Flowchart:

Flowchart: Convert a given string to camelcase.

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Python: Tips of the Day

Check if a given key already exists in a dictionary:

In is the intended way to test for the existence of a key in a dict.

d = {"key1": 10, "key2": 23}

if "key1" in d:
    print("this will execute")

if "nonexistent key" in d:
    print("this will not")

If you wanted a default, you can always use dict.get():

d = dict()

for i in range(100):
    key = i % 10
    d[key] = d.get(key, 0) + 1

and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:

from collections import defaultdict

d = defaultdict(int)

for i in range(100):
    d[i % 10] += 1

but in general, the in keyword is the best way to do it.

Ref: https://bit.ly/2XPMRyz