AdventureWorks Database: Find the salary of top ten employees
SQL Query - AdventureWorks: Exercise-120 with Solution
120. From the following table write a query in SQL to find the salary of top ten employees. Return BusinessEntityID, Rate, and rank of employees by salary.
Sample table: HumanResources.EmployeePayHistory
Sample Solution:
SELECT BusinessEntityID, Rate,
RANK() OVER (ORDER BY Rate DESC) AS RankBySalary
FROM HumanResources.EmployeePayHistory AS eph1
WHERE RateChangeDate = (SELECT MAX(RateChangeDate)
FROM HumanResources.EmployeePayHistory AS eph2
WHERE eph1.BusinessEntityID = eph2.BusinessEntityID)
ORDER BY BusinessEntityID
FETCH FIRST 10 ROWS ONLY;
Sample Output:
businessentityid|rate |rankbysalary|
----------------+-------+------------+
1| 125.5| 1|
2|63.4615| 4|
3|43.2692| 11|
4|29.8462| 28|
5|32.6923| 22|
6|32.6923| 22|
7|50.4808| 6|
8|40.8654| 14|
9|40.8654| 14|
10|42.4808| 13|
SQL AdventureWorks Editor:
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SQL: Tips of the Day
Difference between natural join and inner join
One significant difference between INNER JOIN and NATURAL JOIN is the number of columns returned-
Consider:
TableA TableB +------------+----------+ +--------------------+ |Column1 | Column2 | |Column1 | Column3 | +-----------------------+ +--------------------+ | 1 | 2 | | 1 | 3 | +------------+----------+ +---------+----------+
The INNER JOIN of TableA and TableB on Column1 will return
SELECT * FROM TableA AS a INNER JOIN TableB AS b USING (Column1); SELECT * FROM TableA AS a INNER JOIN TableB AS b ON a.Column1 = b.Column1;
+------------+-----------+---------------------+ | a.Column1 | a.Column2 | b.Column1| b.Column3| +------------------------+---------------------+ | 1 | 2 | 1 | 3 | +------------+-----------+----------+----------+
The NATURAL JOIN of TableA and TableB on Column1 will return:
SELECT * FROM TableA NATURAL JOIN TableB +------------+----------+----------+ |Column1 | Column2 | Column3 | +-----------------------+----------+ | 1 | 2 | 3 | +------------+----------+----------+
Ref: https://bit.ly/3AG5CId
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