AdventureWorks Database: A distinct businessentityid must be returned by both queries
135. From the following tables write a query in SQL to fetch distinct businessentityid that are returned by both the specified query. Sort the result set by ascending order on businessentityid.
Sample table: Person.BusinessEntity
businessentityid|rowguid |modifieddate |
----------------+------------------------------------+-----------------------+
1|0c7d8f81-d7b1-4cf0-9c0a-4cd8b6b50087|2017-12-13 13:20:24.150|
2|6648747f-7843-4002-b317-65389684c398|2017-12-13 13:20:24.430|
3|568204da-93d7-42f4-8a7a-4446a144277d|2017-12-13 13:20:24.540|
4|0eff57b9-4f4f-41a6-8867-658c199a5fc0|2017-12-13 13:20:24.570|
5|b82f88d1-ff79-4fd9-8c54-9d24c140f647|2017-12-13 13:20:24.633|
6|1b3d077a-1941-4d6e-8328-f7dc03595565|2017-12-13 13:20:24.680|
7|c1898370-a36f-43a2-987c-0bf24fe3fb82|2017-12-13 13:20:24.727|
8|2b50abb8-abab-412b-a4d0-4fd5ebeb5cbe|2017-12-13 13:20:24.773|
9|5c0ab449-a087-4d8d-834f-3726061b6bfa|2017-12-13 13:20:24.803|
10|0f3cc1d7-f484-4bde-b088-b11ef03e2f52|2017-12-13 13:20:24.850|
11|a417a3d1-00eb-4d7f-b793-f93dc2c5391d|2017-12-13 13:20:24.900|
12|ebd8a50f-322e-4426-a39a-566fd5535b1c|2017-12-13 13:20:24.947|
-- more --
Sample table: Person.Person
businessentityid|persontype|namestyle|title|firstname |middlename |lastname |suffix|emailpromotion|additionalcontactinfo|demographics|rowguid |modifieddate |
----------------+----------+---------+-----+------------------------+----------------+----------------------+------+--------------+---------------------+------------+------------------------------------+-----------------------+
1|EM |false | |Ken |J |Sánchez | | 0| |[XML] |92c4279f-1207-48a3-8448-4636514eb7e2|2009-01-07 00:00:00.000|
2|EM |false | |Terri |Lee |Duffy | | 1| |[XML] |d8763459-8aa8-47cc-aff7-c9079af79033|2008-01-24 00:00:00.000|
3|EM |false | |Roberto | |Tamburello | | 0| |[XML] |e1a2555e-0828-434b-a33b-6f38136a37de|2007-11-04 00:00:00.000|
4|EM |false | |Rob | |Walters | | 0| |[XML] |f2d7ce06-38b3-4357-805b-f4b6b71c01ff|2007-11-28 00:00:00.000|
5|EM |false |Ms. |Gail |A |Erickson | | 0| |[XML] |f3a3f6b4-ae3b-430c-a754-9f2231ba6fef|2007-12-30 00:00:00.000|
6|EM |false |Mr. |Jossef |H |Goldberg | | 0| |[XML] |0dea28fd-effe-482a-afd3-b7e8f199d56f|2013-12-16 00:00:00.000|
7|EM |false | |Dylan |A |Miller | | 2| |[XML] |c45e8ab8-01be-4b76-b215-820c8368181a|2009-02-01 00:00:00.000|
8|EM |false | |Diane |L |Margheim | | 0| |[XML] |a948e590-4a56-45a9-bc9a-160a1cc9d990|2008-12-22 00:00:00.000|
9|EM |false | |Gigi |N |Matthew | | 0| |[XML] |5fc28c0e-6d36-4252-9846-05caa0b1f6c5|2009-01-09 00:00:00.000|
-- more --
Sample Solution:
-- Selecting the common businessentityid values between the BusinessEntity and Person tables filtered by persontype using the INTERSECT operator
SELECT
-- Selecting the businessentityid column from the BusinessEntity table
businessentityid
-- Selecting data from the BusinessEntity table
FROM
person.businessentity
-- Applying the INTERSECT operator to find the common businessentityid values between the two queries
INTERSECT
-- Selecting the businessentityid column from the Person table where persontype is 'IN'
SELECT
businessentityid
-- Selecting data from the Person table, filtering by persontype 'IN'
FROM
person.person
WHERE
person.persontype = 'IN'
-- Ordering the result set by businessentityid
ORDER BY
businessentityid;
Explanation:
- This SQL code retrieves common businessentityid values between the BusinessEntity and Person tables filtered by persontype 'IN' using the INTERSECT operator.
- The first SELECT statement selects businessentityid values from the BusinessEntity table.
- The second SELECT statement selects businessentityid values from the Person table, filtering by persontype 'IN'.
- The INTERSECT operator combines the results of the two SELECT statements and returns only the common businessentityid values present in both tables.
- The result set will contain businessentityid values that exist in both the BusinessEntity and Person tables and are associated with a person of type 'IN'.
- The result set is ordered by businessentityid.
Sample Output:
businessentityid|
----------------+
1699|
1700|
1701|
1702|
1703|
1704|
1705|
1706|
1707|
1708|
1709|
1710|
1711|
...
SQL AdventureWorks Editor:
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