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SQL Challenges-1: Duplicate Emails

SQL Challenges-1: Exercise-5 with Solution

From the following table, write a SQL query to find all the duplicate emails (no upper case letters) of the employees. Return email ids.

Input:

Table: employees

Structure:

FieldTypeNullKeyDefaultExtra
employee_idint(11)YES
employee_namevarchar(255)YES
email_idvarchar(255)YES

Data:

employee_idemployee_nameemail_id
101Liam Alton[email protected]
102Josh Day[email protected]
103Sean Mann[email protected]
104Evan Blake[email protected]
105Toby Scott[email protected]

Sample Solution:

SQL Code(MySQL):

CREATE TABLE IF NOT EXISTS employees(employee_id int, employee_name varchar(255), email_id varchar(255));
TRUNCATE TABLE employees;
INSERT INTO employees (employee_id,employee_name, email_id) VALUES ('101','Liam Alton', '[email protected]');
INSERT INTO employees (employee_id,employee_name, email_id) VALUES ('102','Josh Day', '[email protected]');
INSERT INTO employees (employee_id,employee_name, email_id) VALUES ('103','Sean Mann', '[email protected]');	
INSERT INTO employees (employee_id,employee_name, email_id) VALUES ('104','Evan Blake', '[email protected]');
INSERT INTO employees (employee_id,employee_name, email_id) VALUES ('105','Toby Scott', '[email protected]');
SELECT * FROM employees;

SELECT email_id FROM
(
SELECT email_id, COUNT(email_id) AS nuOfAppearence
FROM employees
GROUP BY email_id
) AS countEmail
WHERE nuOfAppearence> 1;

Sample Output:

email_id     |
-------------|
[email protected]|

Relational Algebra Expression:

Relational Algebra Expression: Consecutive Numbers.

Relational Algebra Tree:

Relational Algebra Tree: Consecutive Numbers.

Solution-1:

SELECT email_id
FROM employees
GROUP BY email_id
HAVING COUNT(email_id) > 1;

Solution-2:

SELECT DISTINCT p1.email_id
FROM employees p1, employees p2
WHERE p1.email_id = p2.email_id AND p1.employee_id != p2.employee_id;

SQL Code Editor:


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SQL: Tips of the Day

How to select the nth row in a SQL database table?

Basically, PostgreSQL and MySQL supports the non-standard:

SELECT...
LIMIT y OFFSET x 

Oracle, DB2 and MSSQL supports the standard windowing functions:

SELECT * FROM (
  SELECT
    ROW_NUMBER() OVER (ORDER BY key ASC) AS rownumber,
    columns
  FROM tablename
) AS foo
WHERE rownumber <= n

Database: SQL

Ref: https://bit.ly/3zPxcD8