﻿ SQL Challenges-1: Customers without any Order - w3resource

# SQL Challenges-1: Customers without any Order

## SQL Challenges-1: Exercise-6 with Solution

From the following tables, write a SQL query to find those customers who never ordered anything. Return customer name.

Input:

Table: customers

Structure:

FieldTypeNullKeyDefaultExtra
customer_idint(11)YES
customer_namevarchar(255)YES

Data:

customer_idcustomer_name
101Liam
102Josh
103Sean
104Evan
105Toby

Table: orders

structure:

order_idcustomer_idorder_dateorder_amount
4011032012-03-084500
4021012012-09-153650
4031022012-06-274800

Sample Solution:

SQL Code(MySQL):

``````CREATE TABLE IF NOT EXISTS customers (customer_id int, customer_name varchar(255));
TRUNCATE TABLE customers;
INSERT INTO customers (customer_id, customer_name) VALUES ('101', 'Liam');
INSERT INTO customers (customer_id, customer_name) VALUES ('102', 'Josh');
INSERT INTO customers (customer_id, customer_name) VALUES ('103', 'Sean');
INSERT INTO customers (customer_id, customer_name) VALUES ('104', 'Evan');
INSERT INTO customers (customer_id, customer_name) VALUES ('105', 'Toby');
CREATE TABLE IF NOT EXISTS orders (order_id int, customer_id int, order_date Date, order_amount int);
TRUNCATE TABLE orders;
INSERT INTO orders (order_id, customer_id,order_date,order_amount) VALUES ('401', '103','2012-03-08','4500');
INSERT INTO orders (order_id, customer_id,order_date,order_amount) VALUES ('402', '101','2012-09-15','3650');
INSERT INTO orders (order_id, customer_id,order_date,order_amount) VALUES ('403', '102','2012-06-27','4800');
SELECT * FROM customers;
SELECT * FROM orders;

SELECT customer_name as customers
FROM customers
WHERE customer_id NOT IN
(
SELECT customer_id FROM orders
);
```
```

Sample Output:

```Customers|
---------|
Evan     |
Toby     |
```

Solution-1:

``````SELECT customer_name AS customers
FROM customers cus
LEFT JOIN orders ord
ON cus.customer_id = ord.customer_id
WHERE ord.customer_id IS NULL;
``````

Solution-2:

``````SELECT customer_name AS Customers
FROM customers WHERE 0 =
(
SELECT COUNT(*) FROM orders
WHERE customers.customer_id = orders.customer_id
);
``````

SQL Code Editor:

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