﻿ SQL: Display the details of the employee BLAZE

# SQL Exercise: Display the details of the employee BLAZE

## SQL employee Database: Exercise-14 with Solution

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14. From the following table, write a SQL query to find the details of the employee ‘BLAZE’.

Sample table: employees

Pictorial Presentation:

Sample Solution:

``````SELECT *
FROM employees
WHERE emp_name = 'BLAZE';
``````

Sample Output:

``` emp_id | emp_name | job_name | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+----------+------------+------------+---------+------------+--------
66928 | BLAZE    | MANAGER  |      68319 | 1991-05-01 | 2750.00 |            |   3001
(1 row)
```

Explanation:

The provided query in SQL that selects all columns from the 'employees' table where the emp_name is 'BLAZE'.

The "WHERE" clause filters the results for all employees whose name is 'BLAZE'.

Relational Algebra Expression:

Relational Algebra Tree:

## Practice Online

Sample Database: employee

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Previous SQL Exercise: Average salaries of the employees works as ANALYST.
Next SQL Exercise: Employees whose commission is more than their salary.

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## SQL: Tips of the Day

MySQL select 10 random rows from 600K rows fast:

```SELECT name
FROM random AS r1 JOIN
(SELECT CEIL(RAND() *
(SELECT MAX(id)
FROM random)) AS id)
AS r2
WHERE r1.id >= r2.id
ORDER BY r1.id ASC
LIMIT 1
```

Ref: https://bit.ly/3GdCTM3

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