﻿ SQL: Employees whose salary is over 3000 after a 25% raise

# SQL Exercise: Employees whose salary is over 3000 after a 25% raise

## SQL employee Database: Exercise-16 with Solution

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16. From the following table, write a SQL query to identify those employees whose salaries exceed 3000 after receiving a 25% salary increase. Return complete information about the employees.

Sample table: employees

Pictorial Presentation:

Sample Solution:

``````SELECT *
FROM employees
WHERE (1.25*salary) > 3000;
``````

Sample Output:

``` emp_id | emp_name | job_name  | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+-----------+------------+------------+---------+------------+--------
68319 | KAYLING  | PRESIDENT |            | 1991-11-18 | 6000.00 |            |   1001
66928 | BLAZE    | MANAGER   |      68319 | 1991-05-01 | 2750.00 |            |   3001
67832 | CLARE    | MANAGER   |      68319 | 1991-06-09 | 2550.00 |            |   1001
65646 | JONAS    | MANAGER   |      68319 | 1991-04-02 | 2957.00 |            |   2001
67858 | SCARLET  | ANALYST   |      65646 | 1997-04-19 | 3100.00 |            |   2001
69062 | FRANK    | ANALYST   |      65646 | 1991-12-03 | 3100.00 |            |   2001
(6 rows)
```

Relational Algebra Expression:

Relational Algebra Tree:

## Practice Online

Sample Database: employee

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Previous SQL Exercise: Employees whose commission is more than their salary.
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## SQL: Tips of the Day

Count the number of occurrences of a string in a VARCHAR field?

```SELECT
title,
description,
ROUND (
(
LENGTH(description)
- LENGTH( REPLACE ( description, "value", "") )
) / LENGTH("value")
) AS count
FROM <table>
```

Ref: https://bit.ly/3PvNdT4