SQL Exercise: List the employee whose designation is ANALYST
SQL employee Database: Exercise-23 with Solution
[An editor is available at the bottom of the page to write and execute the scripts.]
23. From the following table, write a SQL query to find the employee whose designation is ‘ANALYST’. Return employee name, job name and salary.
Sample table: employees
SELECT emp_name, job_name, salary FROM employees WHERE job_name = 'ANALYST';
emp_name | job_name | salary ----------+----------+--------- SCARLET | ANALYST | 3100.00 FRANK | ANALYST | 3100.00 (2 rows)
The provided SQL statement retrieves the "emp_name", "job_name", and "salary" columns from the 'employees' table where the "job_name" column has a value of 'ANALYST'.
The WHERE clause filters the result set for those employees who are working in the designation 'ANALYST'.
Relational Algebra Expression:
Relational Algebra Tree:
Sample Database: employee
Have another way to solve this solution? Contribute your code (and comments) through Disqus.
Previous SQL Exercise: List the employees whose salaries are less than 3500.
Next SQL Exercise: List the employees who have joined in the year 1991.
What is the difficulty level of this exercise?
Test your Programming skills with w3resource's quiz.
SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
- Weekly Trends
- Python Interview Questions and Answers: Comprehensive Guide
- Scala Exercises, Practice, Solution
- Kotlin Exercises practice with solution
- MongoDB Exercises, Practice, Solution
- SQL Exercises, Practice, Solution - JOINS
- Java Basic Programming Exercises
- SQL Subqueries
- Adventureworks Database Exercises
- C# Sharp Basic Exercises
- SQL COUNT() with distinct
- Java Collection Exercises
- SQL COUNT() function
- SQL Inner Join
We are closing our Disqus commenting system for some maintenanace issues. You may write to us at reach[at]yahoo[dot]com or visit us at Facebook