SQL Exercise: List the employee whose designation is ANALYST
SQL employee Database: Exercise-23 with Solution
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23. From the following table, write a SQL query to find the employee whose designation is ‘ANALYST’. Return employee name, job name and salary.
Sample table: employees
Pictorial Presentation:

Sample Solution:
SELECT emp_name,
job_name,
salary
FROM employees
WHERE job_name = 'ANALYST';
Sample Output:
emp_name | job_name | salary ----------+----------+--------- SCARLET | ANALYST | 3100.00 FRANK | ANALYST | 3100.00 (2 rows)
Explanation:
The provided SQL statement retrieves the "emp_name", "job_name", and "salary" columns from the 'employees' table where the "job_name" column has a value of 'ANALYST'.
The WHERE clause filters the result set for those employees who are working in the designation 'ANALYST'.
Relational Algebra Expression:

Relational Algebra Tree:

Practice Online
Sample Database: employee

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Previous SQL Exercise: List the employees whose salaries are less than 3500.
Next SQL Exercise: List the employees who have joined in the year 1991.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
Database: PostgreSQL
Ref: https://bit.ly/3AfYwZI
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