SQL Exercise: List the employees who have joined in the year 1991

SQL employee Database: Exercise-24 with Solution

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24. From the following table, write a SQL query to identify those employees who joined the company in 1991. Return complete information about the employees.

Sample table: employees

Pictorial Presentation:

Sample Solution:

SELECT *
FROM employees
WHERE to_char(hire_date,'YYYY') = '1991';

Sample Output:

 emp_id | emp_name | job_name  | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+-----------+------------+------------+---------+------------+--------
  68319 | KAYLING  | PRESIDENT |            | 1991-11-18 | 6000.00 |            |   1001
  66928 | BLAZE    | MANAGER   |      68319 | 1991-05-01 | 2750.00 |            |   3001
  67832 | CLARE    | MANAGER   |      68319 | 1991-06-09 | 2550.00 |            |   1001
  65646 | JONAS    | MANAGER   |      68319 | 1991-04-02 | 2957.00 |            |   2001
  69062 | FRANK    | ANALYST   |      65646 | 1991-12-03 | 3100.00 |            |   2001
  64989 | ADELYN   | SALESMAN  |      66928 | 1991-02-20 | 1700.00 |     400.00 |   3001
  65271 | WADE     | SALESMAN  |      66928 | 1991-02-22 | 1350.00 |     600.00 |   3001
  66564 | MADDEN   | SALESMAN  |      66928 | 1991-09-28 | 1350.00 |    1500.00 |   3001
  68454 | TUCKER   | SALESMAN  |      66928 | 1991-09-08 | 1600.00 |       0.00 |   3001
  69000 | JULIUS   | CLERK     |      66928 | 1991-12-03 | 1050.00 |            |   3001
(10 rows)

Explanation:

The provided query in SQL that selects all the rows from the 'employees' table where the year value of the "hire_date" column is equal to 1991.

The "to_char" function converts the "hire_date" column to a string representation of the year using the 'YYYY' format. The comparison operator '=' is then used to compare this string to the string '1991'.

Practice Online

Sample Database: employee

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