﻿ SQL: List the employees who joined in the month of APRIL

# SQL Exercise: List the employees who joined in the month of APRIL

## SQL employee Database: Exercise-33 with Solution

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33. From the following table, write a SQL query to find those employees who joined in the month of APRIL. Return complete information about the employees.

Sample table: employees

Pictorial Presentation:

Sample Solution:

``````SELECT *
FROM employees
WHERE to_char(hire_date,'MON') ='APR';
``````

OR

``````SELECT *
FROM employees
WHERE to_char(hire_date,'MON') IN ('APR');
``````

OR

``````SELECT *
FROM employees
WHERE to_char(hire_date,'MON') LIKE 'APR%';
``````

Sample Output:

``` emp_id | emp_name | job_name | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+----------+------------+------------+---------+------------+--------
65646 | JONAS    | MANAGER  |      68319 | 1991-04-02 | 2957.00 |            |   2001
67858 | SCARLET  | ANALYST  |      65646 | 1997-04-19 | 3100.00 |            |   2001
(2 rows)
```

Explanation:

The said query in SQL that selects all columns from the table 'employees' where the hire_date value, after being converted to a character string with the format mask 'MON', is equal to 'APR'.

The to_char function converts the "hire_date" column to a character string with the format mask 'MON', which means that only the abbreviated month name will be displayed in uppercase letters.

The WHERE clause checks if the hire_date value corresponds to the month of April.

## Practice Online

Sample Database: employee

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Previous SQL Exercise: List those employees whose salary contain only 3 digits.
Next SQL Exercise: Employees joined in company before 19th of the month.

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## SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

```db=# SELECT * FROM xxx;
id | section_id | name
----+------------+------
1 |          1 | A
2 |          1 | B
3 |          1 | C
4 |          1 | D
5 |          2 | E
6 |          2 | F
7 |          3 | G
8 |          2 | H
(8 rows)
```

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

```id | section_id | name
----+------------+------
1 |          1 | A
2 |          1 | B
5 |          2 | E
6 |          2 | F
7 |          3 | G
(5 rows)
```

PostgreSQL v9.3 you can do a lateral join

```select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
select * from t t_inner
where t_inner.section_id = t_outer.section_id
order by t_inner.name
limit 2
) t_top on true
order by t_outer.section_id;
```

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI

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