SQL Exercise: List the employees who joined in the month of APRIL
SQL employee Database: Exercise-33 with Solution
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33. From the following table, write a SQL query to find those employees who joined in the month of APRIL. Return complete information about the employees.
Sample table: employees
Pictorial Presentation:

Sample Solution:
SELECT *
FROM employees
WHERE to_char(hire_date,'MON') ='APR';
OR
SELECT *
FROM employees
WHERE to_char(hire_date,'MON') IN ('APR');
OR
SELECT *
FROM employees
WHERE to_char(hire_date,'MON') LIKE 'APR%';
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 67858 | SCARLET | ANALYST | 65646 | 1997-04-19 | 3100.00 | | 2001 (2 rows)
Explanation:
The said query in SQL that selects all columns from the table 'employees' where the hire_date value, after being converted to a character string with the format mask 'MON', is equal to 'APR'.
The to_char function converts the "hire_date" column to a character string with the format mask 'MON', which means that only the abbreviated month name will be displayed in uppercase letters.
The WHERE clause checks if the hire_date value corresponds to the month of April.
Practice Online
Sample Database: employee

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Previous SQL Exercise: List those employees whose salary contain only 3 digits.
Next SQL Exercise: Employees joined in company before 19th of the month.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
Database: PostgreSQL
Ref: https://bit.ly/3AfYwZI
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