w3resource

SQL Exercise: List the employees who joined in the month of APRIL

SQL employee Database: Exercise-33 with Solution

[An editor is available at the bottom of the page to write and execute the scripts.]

33. From the following table, write a SQL query to find those employees who joined in the month of APRIL. Return complete information about the employees.

Sample table: employees


Pictorial Presentation:

SQL exercises on employee Database: List the employees who joined in the month of APRIL

Sample Solution:

SELECT *
FROM employees
WHERE to_char(hire_date,'MON') ='APR';

OR

SELECT *
FROM employees
WHERE to_char(hire_date,'MON') IN ('APR');

OR

SELECT *
FROM employees
WHERE to_char(hire_date,'MON') LIKE 'APR%';

Sample Output:

 emp_id | emp_name | job_name | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+----------+------------+------------+---------+------------+--------
  65646 | JONAS    | MANAGER  |      68319 | 1991-04-02 | 2957.00 |            |   2001
  67858 | SCARLET  | ANALYST  |      65646 | 1997-04-19 | 3100.00 |            |   2001
(2 rows)

Explanation:

The said query in SQL that selects all columns from the table 'employees' where the hire_date value, after being converted to a character string with the format mask 'MON', is equal to 'APR'.

The to_char function converts the "hire_date" column to a character string with the format mask 'MON', which means that only the abbreviated month name will be displayed in uppercase letters.

The WHERE clause checks if the hire_date value corresponds to the month of April.

Practice Online


Sample Database: employee

employee database structure

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous SQL Exercise: List those employees whose salary contain only 3 digits.
Next SQL Exercise: Employees joined in company before 19th of the month.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.



Follow us on Facebook and Twitter for latest update.

SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

db=# SELECT * FROM xxx;
 id | section_id | name
----+------------+------
  1 |          1 | A
  2 |          1 | B
  3 |          1 | C
  4 |          1 | D
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
  8 |          2 | H
(8 rows)

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

id | section_id | name
----+------------+------
  1 |          1 | A
  2 |          1 | B
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
(5 rows)

PostgreSQL v9.3 you can do a lateral join

select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
    select * from t t_inner
    where t_inner.section_id = t_outer.section_id
    order by t_inner.name
    limit 2
) t_top on true
order by t_outer.section_id;

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI

 





We are closing our Disqus commenting system for some maintenanace issues. You may write to us at reach[at]yahoo[dot]com or visit us at Facebook