﻿ SQL: List the employees who joined in the year 91

SQL Exercise: List the employees who joined in the year 91

SQL employee Database: Exercise-42 with Solution

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42. From the following table, write a SQL query to find those employees who joined in the year 1991. Return complete information about the employees.

Sample table: employees

Pictorial Presentation:

Sample Solution:

``````SELECT *
FROM employees
WHERE hire_date BETWEEN '1991-01-01' AND '1991-12-31';
``````

Sample Output:

```  emp_id | emp_name | job_name  | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+-----------+------------+------------+---------+------------+--------
68319 | KAYLING  | PRESIDENT |            | 1991-11-18 | 6000.00 |            |   1001
66928 | BLAZE    | MANAGER   |      68319 | 1991-05-01 | 2750.00 |            |   3001
67832 | CLARE    | MANAGER   |      68319 | 1991-06-09 | 2550.00 |            |   1001
65646 | JONAS    | MANAGER   |      68319 | 1991-04-02 | 2957.00 |            |   2001
69062 | FRANK    | ANALYST   |      65646 | 1991-12-03 | 3100.00 |            |   2001
64989 | ADELYN   | SALESMAN  |      66928 | 1991-02-20 | 1700.00 |     400.00 |   3001
65271 | WADE     | SALESMAN  |      66928 | 1991-02-22 | 1350.00 |     600.00 |   3001
66564 | MADDEN   | SALESMAN  |      66928 | 1991-09-28 | 1350.00 |    1500.00 |   3001
68454 | TUCKER   | SALESMAN  |      66928 | 1991-09-08 | 1600.00 |       0.00 |   3001
69000 | JULIUS   | CLERK     |      66928 | 1991-12-03 | 1050.00 |            |   3001
(10 rows)
```

Explanation:

The said query in SQL that selects all columns and rows from the 'employees' table where the "hire_date" column falls between the dates '1991-01-01' and '1991-12-31'. This would return a list of all employees who were hired in the year 1991.

The WHERE clause include all of those employees hired during the time '1991-01-01' and '1991-12-31'.

The "BETWEEN" operator is inclusive, so employees hired on December 31st, 1991 would be included in the results.

Relational Algebra Expression:

Relational Algebra Tree:

Practice Online

Sample Database: employee

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Previous SQL Exercise: All employees except those who joined in February.
Next SQL Exercise: List the employees who joined in June 1991.

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SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

```db=# SELECT * FROM xxx;
id | section_id | name
----+------------+------
1 |          1 | A
2 |          1 | B
3 |          1 | C
4 |          1 | D
5 |          2 | E
6 |          2 | F
7 |          3 | G
8 |          2 | H
(8 rows)
```

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

```id | section_id | name
----+------------+------
1 |          1 | A
2 |          1 | B
5 |          2 | E
6 |          2 | F
7 |          3 | G
(5 rows)
```

PostgreSQL v9.3 you can do a lateral join

```select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
select * from t t_inner
where t_inner.section_id = t_outer.section_id
order by t_inner.name
limit 2
) t_top on true
order by t_outer.section_id;
```

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI

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