SQL Exercise: List the employees who joined in June 1991

SQL employee Database: Exercise-43 with Solution

[An editor is available at the bottom of the page to write and execute the scripts.]

43. From the following table, write a SQL query to identify the employees who joined the company in June 1991. Return complete information about the employees.

Sample table: employees

Pictorial Presentation:

Sample Solution:

SELECT *
FROM employees
WHERE hire_date BETWEEN '1991-06-01' AND '1991-06-30';

OR

SELECT *
FROM employees
WHERE to_char(hire_date,'mon-yyyy')='jun-1991'

Sample Output:

 emp_id | emp_name | job_name | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+----------+------------+------------+---------+------------+--------
  67832 | CLARE    | MANAGER  |      68319 | 1991-06-09 | 2550.00 |            |   1001
(1 row)

Explanation:

The said query in that selects all columns and rows from the 'employees' table where the "hire_date" column, after being formatted as a string with the 'mon-yyyy' format, is equal to the string 'jun-1991'.

The WHERE clause includes those employees hired in June 1991.

The "to_char" function is used to convert the hire_date column into a string with the specified format, 'mon-yyyy'. The 'mon' format code represents the abbreviated month name (e.g. Jan, Feb, Mar), while 'yyyy' represents the year in four digits.

Relational Algebra Expression:

Relational Algebra Tree:

Practice Online

Sample Database: employee

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous SQL Exercise: List the employees who joined in the year 91.
Next SQL Exercise: List the employees with annual salaries in a ranges.