SQL exercises on employee Database: List the employees who joined in the month of June in 1991
SQL employee Database: Exercise-43 with Solution
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43. From the following table, write a SQL query to find those employees who joined in the month of June 1991. Return complete information about the employees.
Sample table: employees
Pictorial Presentation:

Sample Solution:
SELECT *
FROM employees
WHERE hire_date BETWEEN '1991-06-01' AND '1991-06-30';
OR
SELECT *
FROM employees
WHERE to_char(hire_date,'mon-yyyy')='jun-1991'
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 (1 row)
Relational Algebra Expression:

Relational Algebra Tree:

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Sample Database: employee

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Previous: From the following table, write a SQL query to find those employees who joined in the year 91. Return complete information about the employees.
Next: From the following table, write a SQL query to find all the employees whose annual salary is within the range 24000 and 50000 (Begin and end values are included.). Return complete information about the employees.
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SQL: Tips of the Day
Delete all Duplicate Rows except for One in MySQL?
SELECT * FROM names; +----+--------+ | id | name | +----+--------+ | 1 | google | | 2 | yahoo | | 3 | msn | | 4 | google | | 5 | google | | 6 | yahoo | +----+--------+
1. If you want to keep the row with the lowest id value:
DELETE n1 FROM names n1, names n2 WHERE n1.id > n2.id AND n1.name = n2.name
2. If you want to keep the row with the highest id value:
DELETE n1 FROM names n1, names n2 WHERE n1.id < n2.id AND n1.name = n2.name
Ref: https://bit.ly/3NroM8o
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