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SQL exercises on employee Database: List the employees who joined in the month of June in 1991

SQL employee Database: Exercise-43 with Solution

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43. From the following table, write a SQL query to find those employees who joined in the month of June 1991. Return complete information about the employees.

Sample table: employees


Pictorial Presentation:

SQL exercises on employee Database: List the employees who joined in the month of June in 1991

Sample Solution:

SELECT *
FROM employees
WHERE hire_date BETWEEN '1991-06-01' AND '1991-06-30';

OR

SELECT *
FROM employees
WHERE to_char(hire_date,'mon-yyyy')='jun-1991'

Sample Output:

 emp_id | emp_name | job_name | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+----------+------------+------------+---------+------------+--------
  67832 | CLARE    | MANAGER  |      68319 | 1991-06-09 | 2550.00 |            |   1001
(1 row)

Relational Algebra Expression:

Relational Algebra Expression: List the employees who joined in the month of June in 1991.

Relational Algebra Tree:

Relational Algebra Tree: List the employees who joined in the month of June in 1991.

Practice Online


Sample Database: employee

employee database structure

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Previous: From the following table, write a SQL query to find those employees who joined in the year 91. Return complete information about the employees.
Next: From the following table, write a SQL query to find all the employees whose annual salary is within the range 24000 and 50000 (Begin and end values are included.). Return complete information about the employees.

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SQL: Tips of the Day

Delete all Duplicate Rows except for One in MySQL?

SELECT * FROM names;

+----+--------+
| id | name   |
+----+--------+
| 1  | google |
| 2  | yahoo  |
| 3  | msn    |
| 4  | google |
| 5  | google |
| 6  | yahoo  |
+----+--------+

1. If you want to keep the row with the lowest id value:

DELETE n1 FROM names n1, names n2 WHERE n1.id > n2.id AND n1.name = n2.name

2. If you want to keep the row with the highest id value:

DELETE n1 FROM names n1, names n2 WHERE n1.id < n2.id AND n1.name = n2.name

Ref: https://bit.ly/3NroM8o