SQL Exercise: List the employees who joined in June 1991
SQL employee Database: Exercise-43 with Solution
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43. From the following table, write a SQL query to identify the employees who joined the company in June 1991. Return complete information about the employees.
Sample table: employees
Pictorial Presentation:
Sample Solution:
SELECT *
FROM employees
WHERE hire_date BETWEEN '1991-06-01' AND '1991-06-30';
OR
SELECT *
FROM employees
WHERE to_char(hire_date,'mon-yyyy')='jun-1991'
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 (1 row)
Explanation:
The said query in that selects all columns and rows from the 'employees' table where the "hire_date" column, after being formatted as a string with the 'mon-yyyy' format, is equal to the string 'jun-1991'.
The WHERE clause includes those employees hired in June 1991.
The "to_char" function is used to convert the hire_date column into a string with the specified format, 'mon-yyyy'. The 'mon' format code represents the abbreviated month name (e.g. Jan, Feb, Mar), while 'yyyy' represents the year in four digits.
Relational Algebra Expression:
Relational Algebra Tree:
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Sample Database: employee
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