SQL Exercise: Employees with Hire date in format February 22, 1991
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7. From the following table, write a SQL query to find those employees with hire date in the format like February 22, 1991. Return employee ID, employee name, salary, hire date.
Sample table: employees
+-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+ | EMPLOYEE_ID | FIRST_NAME | LAST_NAME | EMAIL | PHONE_NUMBER | HIRE_DATE | JOB_ID | SALARY | COMMISSION_PCT | MANAGER_ID | DEPARTMENT_ID | +-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+ | 100 | Steven | King | SKING | 515.123.4567 | 2003-06-17 | AD_PRES | 24000.00 | 0.00 | 0 | 90 | | 101 | Neena | Kochhar | NKOCHHAR | 515.123.4568 | 2005-09-21 | AD_VP | 17000.00 | 0.00 | 100 | 90 | | 102 | Lex | De Haan | LDEHAAN | 515.123.4569 | 2001-01-13 | AD_VP | 17000.00 | 0.00 | 100 | 90 | | 103 | Alexander | Hunold | AHUNOLD | 590.423.4567 | 2006-01-03 | IT_PROG | 9000.00 | 0.00 | 102 | 60 | | 104 | Bruce | Ernst | BERNST | 590.423.4568 | 2007-05-21 | IT_PROG | 6000.00 | 0.00 | 103 | 60 | | 105 | David | Austin | DAUSTIN | 590.423.4569 | 2005-06-25 | IT_PROG | 4800.00 | 0.00 | 103 | 60 | | 106 | Valli | Pataballa | VPATABAL | 590.423.4560 | 2006-02-05 | IT_PROG | 4800.00 | 0.00 | 103 | 60 | | 107 | Diana | Lorentz | DLORENTZ | 590.423.5567 | 2007-02-07 | IT_PROG | 4200.00 | 0.00 | 103 | 60 | | 108 | Nancy | Greenberg | NGREENBE | 515.124.4569 | 2002-08-17 | FI_MGR | 12008.00 | 0.00 | 101 | 100 | | 109 | Daniel | Faviet | DFAVIET | 515.124.4169 | 2002-08-16 | FI_ACCOUNT | 9000.00 | 0.00 | 108 | 100 | ......... | 206 | William | Gietz | WGIETZ | 515.123.8181 | 2002-06-07 | AC_ACCOUNT | 8300.00 | 0.00 | 205 | 110 | +-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+
Pictorial Presentation:
Sample Solution:
SELECT emp_id,
emp_name,
salary,
to_char(hire_date,'MONTH DD,YYYY')
FROM employees;
Sample Output:
emp_id | emp_name | salary | to_char --------+----------+---------+------------------- 68319 | KAYLING | 6000.00 | NOVEMBER 18,1991 66928 | BLAZE | 2750.00 | MAY 01,1991 67832 | CLARE | 2550.00 | JUNE 09,1991 65646 | JONAS | 2957.00 | APRIL 02,1991 67858 | SCARLET | 3100.00 | APRIL 19,1997 69062 | FRANK | 3100.00 | DECEMBER 03,1991 63679 | SANDRINE | 900.00 | DECEMBER 18,1990 64989 | ADELYN | 1700.00 | FEBRUARY 20,1991 65271 | WADE | 1350.00 | FEBRUARY 22,1991 66564 | MADDEN | 1350.00 | SEPTEMBER 28,1991 68454 | TUCKER | 1600.00 | SEPTEMBER 08,1991 68736 | ADNRES | 1200.00 | MAY 23,1997 69000 | JULIUS | 1050.00 | DECEMBER 03,1991 69324 | MARKER | 1400.00 | JANUARY 23,1992 (14 rows)
Explanation:
The provided query in SQL that retrieves the employee ID, employee name, salary, and hire date of all employees from the 'employees' table. The hire date will be formatted as a string in the "MONTH DD,YYYY" format. The "to_char" function is used to format the "hire_date" column as a string in the format "MONTH DD,YYYY".Go to:
PREV : Produce the output of employees.
NEXT : Without the spaces, count each employee name characters.
Practice Online
Sample Database: employees
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