﻿ SQL: Without the spaces, count each employee name characters

# SQL Exercise: Without the spaces, count each employee name characters

## SQL employee Database: Exercise-8 with Solution

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8. From the following table, write a SQL query to count the number of characters except the spaces for each employee name. Return employee name length.

Sample table: employees

Pictorial Presentation:

Sample Solution:

``````SELECT length(trim(emp_name))
FROM employees;
``````

Sample Output:

``` length
--------
7
5
5
5
7
5
8
6
4
6
6
6
6
6
(14 rows)
```

Explanation:

The given query in SQL that selects the length of the trimmed employee names for all rows in the 'employees' table.

In the "trim" function, leading or trailing spaces are removed from the employee name, and the "length" function returns the length.

## Practice Online

Sample Database: employee

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Previous SQL Exercise: Employees with Hiredate in format February 22, 1991.
Next SQL Exercise: List employees id, salary, and commission.

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## SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

```db=# SELECT * FROM xxx;
id | section_id | name
----+------------+------
1 |          1 | A
2 |          1 | B
3 |          1 | C
4 |          1 | D
5 |          2 | E
6 |          2 | F
7 |          3 | G
8 |          2 | H
(8 rows)
```

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

```id | section_id | name
----+------------+------
1 |          1 | A
2 |          1 | B
5 |          2 | E
6 |          2 | F
7 |          3 | G
(5 rows)
```

PostgreSQL v9.3 you can do a lateral join

```select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
select * from t t_inner
where t_inner.section_id = t_outer.section_id
order by t_inner.name
limit 2
) t_top on true
order by t_outer.section_id;
```

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI

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