﻿ SQL: Sort the employees in ascending order on the salary

# SQL Exercise: Sort the employees in ascending order on the salary

## SQL employee Database: Exercise-74 with Solution

[An editor is available at the bottom of the page to write and execute the scripts.]

74. From the following table, write a SQL query to list the employees in ascending order based on salary. Return complete information about the employees.

Sample table: employees

Sample Solution:

``````SELECT *
FROM employees
ORDER BY salary ASC;
``````

Sample Output:

``` emp_id | emp_name | job_name  | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+-----------+------------+------------+---------+------------+--------
63679 | SANDRINE | CLERK     |      69062 | 1990-12-18 |  900.00 |            |   2001
69000 | JULIUS   | CLERK     |      66928 | 1991-12-03 | 1050.00 |            |   3001
68736 | ADNRES   | CLERK     |      67858 | 1997-05-23 | 1200.00 |            |   2001
65271 | WADE     | SALESMAN  |      66928 | 1991-02-22 | 1350.00 |     600.00 |   3001
66564 | MADDEN   | SALESMAN  |      66928 | 1991-09-28 | 1350.00 |    1500.00 |   3001
69324 | MARKER   | CLERK     |      67832 | 1992-01-23 | 1400.00 |            |   1001
68454 | TUCKER   | SALESMAN  |      66928 | 1991-09-08 | 1600.00 |       0.00 |   3001
64989 | ADELYN   | SALESMAN  |      66928 | 1991-02-20 | 1700.00 |     400.00 |   3001
67832 | CLARE    | MANAGER   |      68319 | 1991-06-09 | 2550.00 |            |   1001
66928 | BLAZE    | MANAGER   |      68319 | 1991-05-01 | 2750.00 |            |   3001
65646 | JONAS    | MANAGER   |      68319 | 1991-04-02 | 2957.00 |            |   2001
69062 | FRANK    | ANALYST   |      65646 | 1991-12-03 | 3100.00 |            |   2001
67858 | SCARLET  | ANALYST   |      65646 | 1997-04-19 | 3100.00 |            |   2001
68319 | KAYLING  | PRESIDENT |            | 1991-11-18 | 6000.00 |            |   1001
(14 rows)
```

Explanation:

The said query in SQL that selects all columns from the 'employees' table and order the results by the "salary" column in ascending order.

This means that the query will return all employee records, but the records with the lowest salaries will appear first.

Relational Algebra Expression:

Relational Algebra Tree:

## Practice Online

Sample Database: employee

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Previous SQL Exercise: Sort the employees by salary less than 1000.
Next SQL Exercise: Ascending by job name and descending by employee ID.

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﻿

## SQL: Tips of the Day

Concatenate strings of a string field in a PostgreSQL 'group by' query:

Input:

```ID   COMPANY_ID   EMPLOYEE
1    1            Anna
2    1            Bill
3    2            Carol
4    2            Dave
```
```SELECT company_id, string_agg(employee, ', ')
FROM mytable
GROUP BY company_id;
```

Output:

```COMPANY_ID   EMPLOYEE
1            Anna, Bill
2            Carol, Dave
```

Database: PostgreSQL

Ref: https://bit.ly/2XTiRjq

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