SQL Exercise: Ascending by job name and descending by employee ID
SQL employee Database: Exercise-75 with Solution
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75. From the following table, write a SQL query to list the employees in the ascending order by job title and in descending order by employee ID. Return complete information about the employees.
Sample table: employees
Pictorial Presentation:
Sample Solution:
SELECT *
FROM employees e
ORDER BY e.job_name ASC,
e.emp_id DESC ;
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 69062 | FRANK | ANALYST | 65646 | 1991-12-03 | 3100.00 | | 2001 67858 | SCARLET | ANALYST | 65646 | 1997-04-19 | 3100.00 | | 2001 69324 | MARKER | CLERK | 67832 | 1992-01-23 | 1400.00 | | 1001 69000 | JULIUS | CLERK | 66928 | 1991-12-03 | 1050.00 | | 3001 68736 | ADNRES | CLERK | 67858 | 1997-05-23 | 1200.00 | | 2001 63679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 68454 | TUCKER | SALESMAN | 66928 | 1991-09-08 | 1600.00 | 0.00 | 3001 66564 | MADDEN | SALESMAN | 66928 | 1991-09-28 | 1350.00 | 1500.00 | 3001 65271 | WADE | SALESMAN | 66928 | 1991-02-22 | 1350.00 | 600.00 | 3001 64989 | ADELYN | SALESMAN | 66928 | 1991-02-20 | 1700.00 | 400.00 | 3001 (14 rows)
Explanation:
The provided query in SQL that selects all columns from the 'employees' table and order the results first in ascending order on "job_name" column then for the group of same job_name the records will be sorted by the "emp_id" column in descending order.
It can be said that the records with the same "job_name" value makes a groups together, and the groups appears in alphabetical order and within each group of records with the same "job_name" value the the "emp_id" column will come from highest to lowest value.
Relational Algebra Expression:
Relational Algebra Tree:
Practice Online
Sample Database: employee
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Previous SQL Exercise: Sort the employees in ascending order on the salary.
Next SQL Exercise: Sort unique jobs by department in descending order.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
select * from t t_inner
where t_inner.section_id = t_outer.section_id
order by t_inner.name
limit 2
) t_top on true
order by t_outer.section_id;
Database: PostgreSQL
Ref: https://bit.ly/3AfYwZI
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