﻿ SQL: Employees except given job in ASC order of salaries

SQL Exercise: Employees except given job in ASC order of salaries

SQL employee Database: Exercise-77 with Solution

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77. From the following table, write a SQL query to list all the employees except the PRESIDENT and the MANAGER in ascending order of salaries. Return complete information about the employees.

Pictorial Presentation:

Sample table: employees

Sample Solution:

``````SELECT *
FROM employees
WHERE job_name NOT IN ('PRESIDENT',
'MANAGER')
ORDER BY salary ASC;
``````

Sample Output:

``` emp_id | emp_name | job_name | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+----------+------------+------------+---------+------------+--------
63679 | SANDRINE | CLERK    |      69062 | 1990-12-18 |  900.00 |            |   2001
69000 | JULIUS   | CLERK    |      66928 | 1991-12-03 | 1050.00 |            |   3001
68736 | ADNRES   | CLERK    |      67858 | 1997-05-23 | 1200.00 |            |   2001
66564 | MADDEN   | SALESMAN |      66928 | 1991-09-28 | 1350.00 |    1500.00 |   3001
65271 | WADE     | SALESMAN |      66928 | 1991-02-22 | 1350.00 |     600.00 |   3001
69324 | MARKER   | CLERK    |      67832 | 1992-01-23 | 1400.00 |            |   1001
68454 | TUCKER   | SALESMAN |      66928 | 1991-09-08 | 1600.00 |       0.00 |   3001
64989 | ADELYN   | SALESMAN |      66928 | 1991-02-20 | 1700.00 |     400.00 |   3001
69062 | FRANK    | ANALYST  |      65646 | 1991-12-03 | 3100.00 |            |   2001
67858 | SCARLET  | ANALYST  |      65646 | 1997-04-19 | 3100.00 |            |   2001
(10 rows)
```

Explanation:

The said query in SQL that selects all columns of employees from ‘employees’ table whose job names are not 'PRESIDENT' or 'MANAGER', and orders the results in ascending order by salary.

The WHERE clause with NOT IN operator filters the results to include only those employees whose job name is not 'PRESIDENT' or 'MANAGER'.

The ORDER BY clause specifies that the results should be ordered by salary in ascending order.

Relational Algebra Expression:

Relational Algebra Tree:

Practice Online

Sample Database: employee

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Previous SQL Exercise: Sort unique jobs by department in descending order.
Next SQL Exercise: Sort employees in ascending order by annual salary.

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SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

```db=# SELECT * FROM xxx;
id | section_id | name
----+------------+------
1 |          1 | A
2 |          1 | B
3 |          1 | C
4 |          1 | D
5 |          2 | E
6 |          2 | F
7 |          3 | G
8 |          2 | H
(8 rows)
```

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

```id | section_id | name
----+------------+------
1 |          1 | A
2 |          1 | B
5 |          2 | E
6 |          2 | F
7 |          3 | G
(5 rows)
```

PostgreSQL v9.3 you can do a lateral join

```select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
select * from t t_inner
where t_inner.section_id = t_outer.section_id
order by t_inner.name
limit 2
) t_top on true
order by t_outer.section_id;
```

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI

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