SQL Exercise: Sort employees in ascending order by annual salary

SQL employee Database: Exercise-78 with Solution

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78. From the following table, write a SQL query to find the employees whose annual salary is less than $25,000 per year. Sort the result set in ascending order of the salary. Return complete information about the employees.

Pictorial Presentation:

Sample table: employees

Sample Solution:

SELECT *
FROM employees
WHERE (12*salary) < 25000
ORDER BY salary ASC;

Sample Output:

 emp_id | emp_name | job_name | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+----------+------------+------------+---------+------------+--------
  63679 | SANDRINE | CLERK    |      69062 | 1990-12-18 |  900.00 |            |   2001
  69000 | JULIUS   | CLERK    |      66928 | 1991-12-03 | 1050.00 |            |   3001
  68736 | ADNRES   | CLERK    |      67858 | 1997-05-23 | 1200.00 |            |   2001
  65271 | WADE     | SALESMAN |      66928 | 1991-02-22 | 1350.00 |     600.00 |   3001
  66564 | MADDEN   | SALESMAN |      66928 | 1991-09-28 | 1350.00 |    1500.00 |   3001
  69324 | MARKER   | CLERK    |      67832 | 1992-01-23 | 1400.00 |            |   1001
  68454 | TUCKER   | SALESMAN |      66928 | 1991-09-08 | 1600.00 |       0.00 |   3001
  64989 | ADELYN   | SALESMAN |      66928 | 1991-02-20 | 1700.00 |     400.00 |   3001
(8 rows)

Explanation:

The said query in SQL that selects all columns of employees from 'employees' table whose annual salary is less than 25000, and orders the results in ascending order by salary.

The WHERE clause filters the results to include only those employees whose annual salary, calculated by multiplying their monthly salary by 12, is less than 25000.

The ORDER BY clause ordered the results by salary in ascending order.

Relational Algebra Expression:

Relational Algebra Tree:

Practice Online

Sample Database: employee

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