﻿ SQL: Sort employees in ascending order by annual salary

# SQL Exercise: Sort employees in ascending order by annual salary

## SQL employee Database: Exercise-78 with Solution

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78. From the following table, write a SQL query to find the employees whose annual salary is less than \$25,000 per year. Sort the result set in ascending order of the salary. Return complete information about the employees.

Pictorial Presentation:

Sample table: employees

Sample Solution:

``````SELECT *
FROM employees
WHERE (12*salary) < 25000
ORDER BY salary ASC;
``````

Sample Output:

``` emp_id | emp_name | job_name | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+----------+------------+------------+---------+------------+--------
63679 | SANDRINE | CLERK    |      69062 | 1990-12-18 |  900.00 |            |   2001
69000 | JULIUS   | CLERK    |      66928 | 1991-12-03 | 1050.00 |            |   3001
68736 | ADNRES   | CLERK    |      67858 | 1997-05-23 | 1200.00 |            |   2001
65271 | WADE     | SALESMAN |      66928 | 1991-02-22 | 1350.00 |     600.00 |   3001
66564 | MADDEN   | SALESMAN |      66928 | 1991-09-28 | 1350.00 |    1500.00 |   3001
69324 | MARKER   | CLERK    |      67832 | 1992-01-23 | 1400.00 |            |   1001
68454 | TUCKER   | SALESMAN |      66928 | 1991-09-08 | 1600.00 |       0.00 |   3001
64989 | ADELYN   | SALESMAN |      66928 | 1991-02-20 | 1700.00 |     400.00 |   3001
(8 rows)
```

Explanation:

The said query in SQL that selects all columns of employees from 'employees' table whose annual salary is less than 25000, and orders the results in ascending order by salary.

The WHERE clause filters the results to include only those employees whose annual salary, calculated by multiplying their monthly salary by 12, is less than 25000.

The ORDER BY clause ordered the results by salary in ascending order.

Relational Algebra Expression:

Relational Algebra Tree:

## Practice Online

Sample Database: employee

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Previous SQL Exercise: Employees except given job in ASC order of salaries.
Next SQL Exercise: Employees work as SALESMEN, sorted by their salary.

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## SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

```db=# SELECT * FROM xxx;
id | section_id | name
----+------------+------
1 |          1 | A
2 |          1 | B
3 |          1 | C
4 |          1 | D
5 |          2 | E
6 |          2 | F
7 |          3 | G
8 |          2 | H
(8 rows)
```

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

```id | section_id | name
----+------------+------
1 |          1 | A
2 |          1 | B
5 |          2 | E
6 |          2 | F
7 |          3 | G
(5 rows)
```

PostgreSQL v9.3 you can do a lateral join

```select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
select * from t t_inner
where t_inner.section_id = t_outer.section_id
order by t_inner.name
limit 2
) t_top on true
order by t_outer.section_id;
```

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI

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