SQL Exercise: Employees in ASC order of salary in department 1001
SQL employee Database: Exercise-89 with Solution
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89. From the following table, write a SQL query to find those employees who work in the department 1001. Sort the result-set in ascending order by salary. Return employee ID, employee name, salary and department ID.
Sample table: employees
Sample Solution:
SELECT e.emp_id,
e.emp_name,
e.salary,
e.dep_id
FROM employees E
WHERE e.dep_id = 1001
ORDER BY e.salary ASC;
Sample Output:
emp_id | emp_name | salary | dep_id --------+----------+---------+-------- 69324 | MARKER | 1400.00 | 1001 67832 | CLARE | 2550.00 | 1001 68319 | KAYLING | 6000.00 | 1001 (3 rows)
Explanation:
The said query in SQL that retrieves a list of all employees from the 'employees' table who belong to department 1001, sorted in ascending order by their salary.
The WHERE clause filters the result to include only employees who belong to the department with ID 1001.
The ORDER BY clause sorts the result in ascending order by the salary column.
Relational Algebra Expression:
Relational Algebra Tree:
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Sample Database: employee
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Previous SQL Exercise: List the employees who are senior to their own MANAGERS.
Next SQL Exercise: Find the highest salary from all the employees.
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