SQL Exercise: List employees salary within min_salary and max_salary

SQL employee Database: Exercise-95 with Solution

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95. From the following table, write a SQL query to find those employees whose salary is in the range of minimum and maximum salary (Begin and end values are included.). Return employee ID, name, salary and grade.

Sample table: employees

Sample table: salary_grade

Sample Solution:

SELECT e.emp_id,
       e.emp_name,
       e.salary,
       s.grade
FROM employees e,
     salary_grade s
WHERE e.salary BETWEEN s.min_sal AND s.max_sal ;

Sample Output:

 emp_id | emp_name | salary  | grade
--------+----------+---------+-------
  63679 | SANDRINE |  900.00 |     1
  68736 | ADNRES   | 1200.00 |     1
  69000 | JULIUS   | 1050.00 |     1
  65271 | WADE     | 1350.00 |     2
  66564 | MADDEN   | 1350.00 |     2
  69324 | MARKER   | 1400.00 |     2
  64989 | ADELYN   | 1700.00 |     3
  68454 | TUCKER   | 1600.00 |     3
  66928 | BLAZE    | 2750.00 |     4
  67832 | CLARE    | 2550.00 |     4
  65646 | JONAS    | 2957.00 |     4
  67858 | SCARLET  | 3100.00 |     4
  69062 | FRANK    | 3100.00 |     4
  68319 | KAYLING  | 6000.00 |     5
(14 rows)

Explanation:

The said query in SQL that selects the employee ID, employee name, salary, and grade from the 'employees' and 'salary_grade' tables where salary falls within the minimum and maximum salary ranges in the 'salary_grade' table.

An implicit cross join builds between the tables 'employees' and 'salary_grade' which means that each row in the 'employees' table is combined with every row in the 'salary_grade' table and the WHERE clause filters the results to include only those employees whose salary falls within the minimum and maximum salary ranges in the 'salary_grade' table.

Relational Algebra Expression:

Relational Algebra Tree:

Practice Online

Sample Database: employee

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