SQL Exercise: List the nurses who are yet to be registered
SQL hospital Database: Exercise-1 with Solution
1. From the following table, write a SQL query to find out which nurses have not yet been registered. Return all the fields of nurse table.
Sample table: nurse
SELECT * FROM nurse WHERE registered='false';
employeeid | name | position | registered | ssn ------------+--------------+----------+------------+----------- 103 | Paul Flowers | Nurse | f | 333333330 (1 row)
The given query in SQL that retrieves all rows from the nurse table where the value of the registered column is 'false'.
The WHERE clause filters the results and returns only the rows where the value of the registered column is 'false'.
Relational Algebra Expression:
Relational Algebra Tree:
E R Diagram of Hospital Database:
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
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