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SQL Exercise: Find the nurse who are the head of their department

SQL hospital Database: Exercise-2 with Solution

2. From the following table, write a SQL query to identify the nurses in charge of each department. Return nursename as “name”, Position as “Position”.

Sample table: nurse


Sample Solution: 

SELECT name AS "Name",
       POSITION AS "Position"
FROM nurse
WHERE POSITION='Head Nurse';

Sample Output:

      Name      |  Position
----------------+------------
 Carla Espinosa | Head Nurse
(1 row)

Explanation:

The said query in SQL that returns a list of names and their respective positions who are working as "Head Nurse" in the "nurse" table. The "AS" keyword is used to alias the column names to "Name" and "Position".

Pictorial presentation:

Find the name of the nurse who are the head of their department

Practice Online


E R Diagram of Hospital Database:

E R Diagram: SQL Hospital Database.

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Previous SQL Exercise: List the nurses who are yet to be registered.
Next SQL Exercise: Physicians who is the head of each department.

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SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

db=# SELECT * FROM xxx;
 id | section_id | name
----+------------+------
  1 |          1 | A
  2 |          1 | B
  3 |          1 | C
  4 |          1 | D
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
  8 |          2 | H
(8 rows)

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

id | section_id | name
----+------------+------
  1 |          1 | A
  2 |          1 | B
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
(5 rows)

PostgreSQL v9.3 you can do a lateral join

select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
    select * from t t_inner
    where t_inner.section_id = t_outer.section_id
    order by t_inner.name
    limit 2
) t_top on true
order by t_outer.section_id;

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI

 

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