SQL Exercise: Find the patients and the physicians who treated them
SQL hospital Database: Exercise-12 with Solution
12. From the following tables, write a SQL query to find the patients with their physicians by whom they received preliminary treatment. Return Patient name as "Patient", address as "Address" and Physician name as "Physician".
Sample table: patient
Sample table: physician
SELECT t.name AS "Patient", t.address AS "Address", p.name AS "Physician" FROM patient t JOIN physician p ON t.pcp=p.employeeid;
Patient | Address | Physician -------------------+--------------------+------------------ John Smith | 42 Foobar Lane | John Dorian Grace Ritchie | 37 Snafu Drive | Elliot Reid Random J. Patient | 101 Omgbbq Street | Elliot Reid Dennis Doe | 1100 Foobaz Avenue | Christopher Turk (4 rows)
The said query in SQL that selects the name and address of patients along with the name of their physician.
The JOIN statement specifies that the patient table should be joined with the physician table using a matching condition where the patient's physician ID pcp matches the physician's employee ID columns.
E R Diagram of Hospital Database:
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Previous SQL Exercise: Name of the physicians who are not a specialized.
Next SQL Exercise: Patients and doctors who gave them preliminary care.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
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