w3resource

SQL Exercise: Find the patients and the physicians who treated them

SQL hospital Database: Exercise-12 with Solution

12. From the following tables, write a SQL query to find the patients with their physicians by whom they received preliminary treatment. Return Patient name as "Patient", address as "Address" and Physician name as "Physician".

Sample table: patient


Sample table: physician


Sample Solution:

SELECT t.name AS "Patient",
       t.address AS "Address",
       p.name AS "Physician"
FROM patient t
JOIN physician p ON t.pcp=p.employeeid;

Sample Output:

      Patient      |      Address       |    Physician
-------------------+--------------------+------------------
 John Smith        | 42 Foobar Lane     | John Dorian
 Grace Ritchie     | 37 Snafu Drive     | Elliot Reid
 Random J. Patient | 101 Omgbbq Street  | Elliot Reid
 Dennis Doe        | 1100 Foobaz Avenue | Christopher Turk
(4 rows)

Explanation:

The said query in SQL that selects the name and address of patients along with the name of their physician.

The JOIN statement specifies that the patient table should be joined with the physician table using a matching condition where the patient's physician ID pcp matches the physician's employee ID columns.

Practice Online


E R Diagram of Hospital Database:

E R Diagram: SQL Hospital Database.

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous SQL Exercise: Name of the physicians who are not a specialized.
Next SQL Exercise: Patients and doctors who gave them preliminary care.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.



Follow us on Facebook and Twitter for latest update.

SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

db=# SELECT * FROM xxx;
 id | section_id | name
----+------------+------
  1 |          1 | A
  2 |          1 | B
  3 |          1 | C
  4 |          1 | D
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
  8 |          2 | H
(8 rows)

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

id | section_id | name
----+------------+------
  1 |          1 | A
  2 |          1 | B
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
(5 rows)

PostgreSQL v9.3 you can do a lateral join

select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
    select * from t t_inner
    where t_inner.section_id = t_outer.section_id
    order by t_inner.name
    limit 2
) t_top on true
order by t_outer.section_id;

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI

 

We are closing our Disqus commenting system for some maintenanace issues. You may write to us at reach[at]yahoo[dot]com or visit us at Facebook