SQL Exercise: Name of the physicians who are not a specialized
SQL hospital Database: Exercise-11 with Solution
11. From the following tables, write a SQL query to identify physicians who are not specialists. Return Physician name as "Physician", position as "Designation".
Sample table: physician
Sample table: trained_in
SELECT p.name AS "Physician", p.position "Designation" FROM physician p LEFT JOIN trained_in t ON p.employeeid=t.physician WHERE t.treatment IS NULL ORDER BY employeeid;
Physician | Designation -------------------+---------------------------- John Dorian | Staff Internist Elliot Reid | Attending Physician Percival Cox | Senior Attending Physician Bob Kelso | Head Chief of Medicine Keith Dudemeister | MD Resident Molly Clock | Attending Psychiatrist (6 rows)
The said query in SQL that selects the name and designation of physicians who are not trained in any treatment from the physician table and a trained_in table.
The left join combines the physician and trained_in tables based on the employeeid and physician columns. It checks whether he physician is trained in any treatment other wise treatment, the trained_in table will have NULL values for that physician.
The WHERE clause is used to filter the results and return only those physicians who are not trained in any treatment.
The resulting output will be a table with two columns labeled "Physician" and "Designation", respectively.
E R Diagram of Hospital Database:
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Previous SQL Exercise: Find physicians who are yet to be affiliated.
Next SQL Exercise: Find the patients and the physicians who treated them.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
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