SQL Exercise: Find physicians who are yet to be affiliated
SQL hospital Database: Exercise-10 with Solution
10. From the following tables, write a SQL query to find those physicians who are yet to be affiliated. Return Physician name as "Physician", Position, and department as "Department".
Sample table: physician
Sample table: affiliated_with
Sample table: department
Sample Solution:
SELECT p.name AS "Physician",
p.position,
d.name AS "Department"
FROM physician p
JOIN affiliated_with a ON a.physician=p.employeeid
JOIN department d ON a.department=d.departmentid
WHERE primaryaffiliation='false';
Sample Output:
Physician | position | Department ------------------+------------------------------+------------------ Christopher Turk | Surgical Attending Physician | General Medicine John Wen | Surgical Attending Physician | General Medicine (2 rows)
Explanation:
The said query in SQL that selects the name, position, and department of physicians who are not primary-affiliated with a department from the table physician, affiliated_with, and department.
The query links the physician and affiliated_with table based on the physician and employeeid columns, and affiliated_with and department table based on the department and departmentid columns. The affiliated_with table contains the foreign keys to the physician and department tables.
The WHERE clause filters the results and return only those physicians who are not primary-affiliated with a department.
The resulting output will be a table with the column headers labeled "Physician", "Position", and "Department", respectively.
Pictorial presentation:

Practice Online
E R Diagram of Hospital Database:

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Previous SQL Exercise: Physicians who are trained in a special treatment.
Next SQL Exercise: Name of the physicians who are not a specialized.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
Database: PostgreSQL
Ref: https://bit.ly/3AfYwZI
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