SQL Exercise: Physicians who are trained in a special treatment
SQL hospital Database: Exercise-9 with Solution
9. From the following tables, write a SQL query to find those physicians who have received special training. Return Physician name as “Physician”, treatment procedure name as “Treatment".
Sample table: physician
Sample table: procedure
Sample table: trained_in
Sample Solution:
SELECT p.name AS "Physician",
c.name AS "Treatment"
FROM physician p,
PROCEDURE c,
trained_in t
WHERE t.physician=p.employeeid
AND t.treatment=c.code;
Sample Output:
Physician | Treatment ------------------+-------------------------------- Christopher Turk | Reverse Rhinopodoplasty Christopher Turk | Obtuse Pyloric Recombobulation Christopher Turk | Obfuscated Dermogastrotomy Christopher Turk | Reversible Pancreomyoplasty Christopher Turk | Follicular Demiectomy Todd Quinlan | Obtuse Pyloric Recombobulation Todd Quinlan | Obfuscated Dermogastrotomy Todd Quinlan | Reversible Pancreomyoplasty John Wen | Reverse Rhinopodoplasty John Wen | Obtuse Pyloric Recombobulation John Wen | Folded Demiophtalmectomy John Wen | Complete Walletectomy John Wen | Obfuscated Dermogastrotomy John Wen | Reversible Pancreomyoplasty John Wen | Follicular Demiectomy (15 rows)
Explanation:
The given query in SQL that selects the name of physicians and the treatments they are trained in from the physician table, procedure table, and trained_in table.
The query combines data from the three tables. It selects the physician name , treatment name from the physician table and the procedure table respectively, and the trained_in table links the physician and treatment on their respective IDs.
The resulting output will be a table with the columns "Physician" and "Treatment".
Pictorial presentation:

Practice Online
E R Diagram of Hospital Database:

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Previous SQL Exercise: Find the name and department of the physician.
Next SQL Exercise: Find physicians who are yet to be affiliated.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
Database: PostgreSQL
Ref: https://bit.ly/3AfYwZI
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