SQL Exercise: Find the name and department of the physician
SQL hospital Database: Exercise-8 with Solution
8. From the following tables, write a SQL query to identify the physician and the department with which he or she is affiliated. Return Physician name as "Physician", and department name as "Department".
Sample table: physician
Sample table: department
Sample table: affiliated_with
SELECT p.name AS "Physician", d.name AS "Department" FROM physician p, department d, affiliated_with a WHERE p.employeeid=a.physician AND a.department=d.departmentid;
Physician | Department -------------------+------------------ John Dorian | General Medicine Elliot Reid | General Medicine Christopher Turk | General Medicine Christopher Turk | Surgery Percival Cox | General Medicine Bob Kelso | General Medicine Todd Quinlan | Surgery John Wen | General Medicine John Wen | Surgery Keith Dudemeister | General Medicine Molly Clock | Psychiatry (11 rows)
The said query in SQL that selects the name of physicians and the department they are affiliated with from the physician table, department table, and affiliated_with table.
The query uses a join to combine data from the three tables. It selects the physician name from the physician table, department name from the department table, and uses the affiliated_with table to link the two. The affiliated_with table contains foreign keys to the physician and department tables, which are used to join the tables on their respective IDs.
The column headers will be labeled "Physician" and "Department", respectively.
E R Diagram of Hospital Database:
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Previous SQL Exercise: Count the number of unavailable rooms.
Next SQL Exercise: Physicians who are trained in a special treatment.
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SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
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