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SQL Exercise: Patients and the room number where they treated

SQL hospital Database: Exercise-15 with Solution

15. From the following tables, write a SQL query to find the names of the patients and the room number where they need to be treated. Return patient name as "Patient", examination room as "Room No.", and starting date time as Date "Date and Time of appointment".

Sample table: patient


Sample table: appointment


Sample Solution:

SELECT p.name AS "Patient",
       a.examinationroom AS "Room No.",
       a.start_dt_time AS "Date and Time of appointment"
FROM patient p
JOIN appointment a ON p.ssn=a.patient;

Sample Output:

      Patient      | Room No. | Date and Time of appointment
-------------------+----------+------------------------------
 John Smith        | A        | 2008-04-24 10:00:00
 Grace Ritchie     | B        | 2008-04-24 10:00:00
 John Smith        | A        | 2008-04-25 10:00:00
 Dennis Doe        | B        | 2008-04-25 10:00:00
 Dennis Doe        | C        | 2008-04-26 10:00:00
 Random J. Patient | C        | 2008-04-26 11:00:00
 John Smith        | C        | 2008-04-26 12:00:00
 Dennis Doe        | A        | 2008-04-27 10:00:00
 Grace Ritchie     | B        | 2008-04-27 10:00:00
(9 rows)

Explanation:

The given query in SQL that returns information about patients and their appointments, including the patient's name, the examination room number, and the date and time of the appointment from two tables "patient" and "appointment".

The query joins the 'patient' and 'appointment' tables based on the ssn and patient columns.

Practice Online


E R Diagram of Hospital Database:

E R Diagram: SQL Hospital Database.

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Previous SQL Exercise: Count unique patients who came to examination room C.
Next SQL Exercise: Nurses and the room where they assist the physicians.

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SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

db=# SELECT * FROM xxx;
 id | section_id | name
----+------------+------
  1 |          1 | A
  2 |          1 | B
  3 |          1 | C
  4 |          1 | D
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
  8 |          2 | H
(8 rows)

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

id | section_id | name
----+------------+------
  1 |          1 | A
  2 |          1 | B
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
(5 rows)

PostgreSQL v9.3 you can do a lateral join

select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
    select * from t t_inner
    where t_inner.section_id = t_outer.section_id
    order by t_inner.name
    limit 2
) t_top on true
order by t_outer.section_id;

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI

 

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