SQL Exercise: Nurses and the room where they assist the physicians

SQL hospital Database: Exercise-16 with Solution

16. From the following tables, write a SQL query to identify the nurses and the room in which they will assist the physicians. Return Nurse Name as "Name of the Nurse" and examination room as "Room No.".

Sample table: nurse

Sample table: appointment

Sample Solution:

SELECT n.name AS "Name of the Nurse",
       a.examinationroom AS "Room No."
FROM nurse n
JOIN appointment a ON a.prepnurse=n.employeeid;

Sample Output:

 Name of the Nurse | Room No.
 Carla Espinosa    | A
 Carla Espinosa    | B
 Laverne Roberts   | A
 Paul Flowers      | B
 Paul Flowers      | C
 Laverne Roberts   | A
 Carla Espinosa    | B
(7 rows)


The said query in SQL that returns information about the nurses who prepared for appointments, along with the examination room number for each appointment from the tables 'nurse' and 'appointment',

The JOIN keyword joins the "nurse" and "appointment" tables based on the employeeid and prepnurse columns.

Practice Online

E R Diagram of Hospital Database:

E R Diagram: SQL Hospital Database.

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Previous SQL Exercise: Patients and the room number where they treated.
Next SQL Exercise: Patients with an appointment on the given date.

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SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

db=# SELECT * FROM xxx;
 id | section_id | name
  1 |          1 | A
  2 |          1 | B
  3 |          1 | C
  4 |          1 | D
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
  8 |          2 | H
(8 rows)

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

id | section_id | name
  1 |          1 | A
  2 |          1 | B
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
(5 rows)

PostgreSQL v9.3 you can do a lateral join

select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
    select * from t t_inner
    where t_inner.section_id = t_outer.section_id
    order by t_inner.name
    limit 2
) t_top on true
order by t_outer.section_id;

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI


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