SQL Exercise: Patients with an appointment on the given date
SQL hospital Database: Exercise-17 with Solution
17. From the following tables, write a SQL query to locate the patients who attended the appointment on the 25th of April at 10 a.m. Return Name of the patient, Name of the Nurse assisting the physician, Physician Name as "Name of the physician", examination room as "Room No.", schedule date and approximate time to meet the physician.
Sample table: patient
Sample table: appointment
Sample table: nurse
Sample table: physician
Sample Solution:
SELECT t.name AS "Name of the patient",
n.name AS "Name of the Nurse assisting the physician",
p.name AS "Name of the physician",
a.examinationroom AS "Room No.",
a.start_dt_time
FROM patient t
JOIN appointment a ON a.patient=t.ssn
JOIN nurse n ON a.prepnurse=n.employeeid
JOIN physician p ON a.physician=p.employeeid
WHERE start_dt_time='2008-04-25 10:00:00';
Sample Output:
Name of the patient | Name of the Nurse assisting the physician | Name of the physician | Room No. | start_dt_time ---------------------+-------------------------------------------+-----------------------+----------+--------------------- John Smith | Laverne Roberts | John Dorian | A | 2008-04-25 10:00:00 Dennis Doe | Paul Flowers | Percival Cox | B | 2008-04-25 10:00:00 (2 rows)
Explanation:
The said query in SQL that returns information about the patient, nurse, physician, examination room number, and start date and time for a specific appointment that took place on April 25, 2008, at 10:00 AM.
The query join the 'patient', 'appointment', 'nurse', and 'physician' tables, based on their common columns.
The 'appointment' and 'patient' tables linked based on the patient and ssn columns, the 'appointment' and 'nurse' tables based on the prepnurse and employeeid columns, and the 'appointment' and 'physician' table based on the physician and employeeid columns.
The query filters the results using a WHERE clause to retrieve only the appointment that took place on April 25, 2008, at 10:00 AM.
Practice Online
E R Diagram of Hospital Database:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.
Previous SQL Exercise: Nurses and the room where they assist the physicians.
Next SQL Exercise: Patients and their physicians who do not need a nurse.
What is the difficulty level of this exercise?
Test your Programming skills with w3resource's quiz.
SQL: Tips of the Day
Grouped LIMIT in PostgreSQL: Show the first N rows for each group?
db=# SELECT * FROM xxx; id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 3 | 1 | C 4 | 1 | D 5 | 2 | E 6 | 2 | F 7 | 3 | G 8 | 2 | H (8 rows)
I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name ----+------------+------ 1 | 1 | A 2 | 1 | B 5 | 2 | E 6 | 2 | F 7 | 3 | G (5 rows)
PostgreSQL v9.3 you can do a lateral join
select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer join lateral ( select * from t t_inner where t_inner.section_id = t_outer.section_id order by t_inner.name limit 2 ) t_top on true order by t_outer.section_id;
Database: PostgreSQL
Ref: https://bit.ly/3AfYwZI
- Weekly Trends
- Python Interview Questions and Answers: Comprehensive Guide
- Scala Exercises, Practice, Solution
- Kotlin Exercises practice with solution
- MongoDB Exercises, Practice, Solution
- SQL Exercises, Practice, Solution - JOINS
- Java Basic Programming Exercises
- SQL Subqueries
- Adventureworks Database Exercises
- C# Sharp Basic Exercises
- SQL COUNT() with distinct
- JavaScript String Exercises
- JavaScript HTML Form Validation
- Java Collection Exercises
- SQL COUNT() function
- SQL Inner Join
We are closing our Disqus commenting system for some maintenanace issues. You may write to us at reach[at]yahoo[dot]com or visit us at Facebook