SQL Exercise: Patients with an appointment on the given date

SQL hospital Database: Exercise-17 with Solution

17. From the following tables, write a SQL query to locate the patients who attended the appointment on the 25th of April at 10 a.m. Return Name of the patient, Name of the Nurse assisting the physician, Physician Name as "Name of the physician", examination room as "Room No.", schedule date and approximate time to meet the physician.

Sample table: patient

Sample table: appointment

Sample table: nurse

Sample table: physician

Sample Solution:

SELECT t.name AS "Name of the patient",
       n.name AS "Name of the Nurse assisting the physician",
       p.name AS "Name of the physician",
       a.examinationroom AS "Room No.",
FROM patient t
JOIN appointment a ON a.patient=t.ssn
JOIN nurse n ON a.prepnurse=n.employeeid
JOIN physician p ON a.physician=p.employeeid
WHERE start_dt_time='2008-04-25 10:00:00';

Sample Output:

 Name of the patient | Name of the Nurse assisting the physician | Name of the physician | Room No. |    start_dt_time
 John Smith          | Laverne Roberts                           | John Dorian           | A        | 2008-04-25 10:00:00
 Dennis Doe          | Paul Flowers                              | Percival Cox          | B        | 2008-04-25 10:00:00
(2 rows)


The said query in SQL that returns information about the patient, nurse, physician, examination room number, and start date and time for a specific appointment that took place on April 25, 2008, at 10:00 AM.

The query join the 'patient', 'appointment', 'nurse', and 'physician' tables, based on their common columns.

The 'appointment' and 'patient' tables linked based on the patient and ssn columns, the 'appointment' and 'nurse' tables based on the prepnurse and employeeid columns, and the 'appointment' and 'physician' table based on the physician and employeeid columns.

The query filters the results using a WHERE clause to retrieve only the appointment that took place on April 25, 2008, at 10:00 AM.

Practice Online

E R Diagram of Hospital Database:

E R Diagram: SQL Hospital Database.

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Previous SQL Exercise: Nurses and the room where they assist the physicians.
Next SQL Exercise: Patients and their physicians who do not need a nurse.

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SQL: Tips of the Day

Grouped LIMIT in PostgreSQL: Show the first N rows for each group?

db=# SELECT * FROM xxx;
 id | section_id | name
  1 |          1 | A
  2 |          1 | B
  3 |          1 | C
  4 |          1 | D
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
  8 |          2 | H
(8 rows)

I need the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:

id | section_id | name
  1 |          1 | A
  2 |          1 | B
  5 |          2 | E
  6 |          2 | F
  7 |          3 | G
(5 rows)

PostgreSQL v9.3 you can do a lateral join

select distinct t_outer.section_id, t_top.id, t_top.name from t t_outer
join lateral (
    select * from t t_inner
    where t_inner.section_id = t_outer.section_id
    order by t_inner.name
    limit 2
) t_top on true
order by t_outer.section_id;

Database: PostgreSQL

Ref: https://bit.ly/3AfYwZI


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